Last visit was: 29 Apr 2026, 17:56 It is currently 29 Apr 2026, 17:56
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 28 Apr 2026
Posts: 16,447
Own Kudos:
79,447
 [3]
Given Kudos: 485
Location: Pune, India
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,447
Kudos: 79,447
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
russ9
Joined: 15 Aug 2013
Last visit: 20 Apr 2015
Posts: 170
Own Kudos:
Given Kudos: 23
Posts: 170
Kudos: 426
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 28 Apr 2026
Posts: 16,447
Own Kudos:
79,447
 [1]
Given Kudos: 485
Location: Pune, India
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,447
Kudos: 79,447
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
erikvm
Joined: 26 Feb 2015
Last visit: 19 Mar 2017
Posts: 92
Own Kudos:
Given Kudos: 43
Posts: 92
Kudos: 237
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasPrepKarishma
russ9




I thought that I understood your line method until I read this statement. Whenever we look at the line method (You usually have an average weight and the two ends(weights) of the data given). So in the example with ages, there are 17yr old girls, 20yr old boys and the group is 18, you have a clear number that's above the average and below the average -- which makes complete sense.

Two questions:
1) Line method:
If I were to use the line method in this example -- we are already TOLD that the middle weight is 40. In addition to that, i'm a little confused because the "middle weight" is actually not in the middle? I'm not sure if I'm explaining this properly but if we are looking to score a 60% (that should be the average of the two ends, correct?) -- we know that we have scored 40% but we don't have the other end (a number higher than 60). How do we find a ratio without knowing that number, which incidentally, is the same number that the question is asking for.

2) If I use the equation:

Weight 1 / Weight 2 = Average 2 - Average. Avg / Average. Avg - A1

We know that the weight of the final is 40% which means that the weight of everything but the exam is 100-40 = 60%. So we have w1=40 and w2 = 60

Additionally, we know that we are looking to score a 60% in the class, which is different than the 60% I outlined above. So we have that the Average. Avg = 60.

We also know that currently, he has scored 45%, which is on the non final part, therefore, we are looking to find what he needs to score on the Final. Correct? Meaning, we need to find A1 in the equation above. Correct?

This seems to get me to 82.5 but it was extremely difficult for me to draw the gap between what weights correspond to what grades. I've read your "quarter wit" documents but it still eludes me a little. Any help would be appreciated.

Thanks.

Scale method:

w1/w2 = (C2 - Cavg)/(Cavg - C1)

Cavg is the thing we need to average - marks here
w1 and w2 are the weights allotted to marks - 40% to finals and 60% to rest of the tests

Question: The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam. What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class?

"The final exam of a particular class makes up 40% of the final grade" - this tells us that weight allotted to final exam is 40% and hence 60% is allotted to exams before finals. So we have w1 and w2. This is the tricky part.

"Moe is failing the class with an average (arithmetic mean) of 45%" - This means in exams before finals, Moe has 45% marks.

"What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class" - To pass, Moe needs average 60% marks i.e. Cavg should be 60%. So what we need is his marks in finals i.e. C2

w1/w2 = (C2 - Cavg)/(Cavg - C1)
60/40 = (C2 - 60)/(60 - 45)

This will give you C2.

This is still quite unclear to me. I too understand the boys and girls problem just fine, but like the previous poster metioned, I don't understand how we get that upper limit. Any chance you can show it on a number line too?
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,906
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The question can be interpreted in an another way

Total marks needed to pass
We are given that out of total marks(let's assume it to be \(y\)) Moe should receive 60% to pass i.e. 60% of \(y\) = \(0.6y\)

Final exam marks
Since the final exam makes up for 40% of the total marks, it constitutes 40% of \(y\) \(= 0.4y\) marks. Let's assume he should get \(x\)% of marks in his final exam to pass the exam i.e. he should get \(x\)% of \(0.4y\)

Rest of the marks
The rest 60% of total marks constitute of 60% of \(y\) \(= 0.6y\) marks

Out of these \(0.6y\) marks, Moe has got only 45% i.e. 45% of \(0.6y = 0.45 * 0.6y\)

Writing the equation
We can write the equation for marks of Moe as

Total marks needed by Moe to pass = Rest of the marks + Final exam marks

\(0.6y = 0.45 * 0.6y +\) \(x\)% \(* 0.4y\)

Solving this would give us \(x = 82.5\)% of marks he needs in his final exam to pass the class

Hope this helps :)

Regards
Harsh
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 28 Apr 2026
Posts: 16,447
Own Kudos:
79,447
 [3]
Given Kudos: 485
Location: Pune, India
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,447
Kudos: 79,447
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
erikvm


This is still quite unclear to me. I too understand the boys and girls problem just fine, but like the previous poster metioned, I don't understand how we get that upper limit. Any chance you can show it on a number line too?

We have condensed the scale method into the formula for ease. They are the same.

In the formula, C2 is unknown and you solve it with simple equation manipulation to get the value of C2 (cross multiply etc).

On the scale, this is how it will look:

Attachment:
Scale Method.jpg
Scale Method.jpg [ 13.16 KiB | Viewed 5816 times ]

Weight given to 45% marks is 60% and weight given to final marks is 40%. So ratio of weights is 3:2. So 45% and final marks will be away from the average in the ratio 2:3 (inverse of 3:2).
45 is actually 15 away from 60 (the 2 of the ratio) so the final marks (C2) will be (15/2)* 3 = 22.5 away from 60. This will take us to 82.5 as C2.
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,057
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi All,

This question can be solved in a variety of ways, depending on how you choose to set up the math (you could also TEST THE ANSWERS here, but you'd likely find the right algebraic approach to be pretty easy).

Since we know that the final exam is 40% of the final grade, we know that it is 2/5 of the final grade. This means that Moe's work so far (the 45% grade) accounts for 3/5 of the final grade. Since we're looking for the minimal score needed on the final exam to raise his grade to 60%, we can set up the following equation:

(3/5)(45%) + (2/5)(X%) = 60%

27 + 2X/5 = 60
2X/5 = 33
X = (5)(33)/2
X = 165/2
X = 82.5

Final Answer:

GMAT assassins aren't born, they're made,
Rich
User avatar
_shashank_shekhar_
Joined: 05 Jan 2017
Last visit: 28 Oct 2018
Posts: 31
Own Kudos:
52
 [1]
Given Kudos: 17
Posts: 31
Kudos: 52
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
by weighted avg:
60=(40*x+60*45)/(60+40)
=> 60*100=40x+2700
=> 40x=6000-2700=3300
=>x=3300/40=82.5 (B)
User avatar
Kritisood
Joined: 21 Feb 2017
Last visit: 19 Jul 2023
Posts: 488
Own Kudos:
1,315
 [1]
Given Kudos: 1,090
Location: India
GMAT 1: 700 Q47 V39
Products:
GMAT 1: 700 Q47 V39
Posts: 488
Kudos: 1,315
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
rxs0005
The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam. What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class?

A. 75%
B. 82.5%
C. 85%
D. 90%
E. 92.5%

This diagram method builds on the same foundations as what others have posted but visualizing it like this seems easier for me personally. Hope this is helpful.
Attachments

IMG_1262 copy.jpg
IMG_1262 copy.jpg [ 89.93 KiB | Viewed 2927 times ]

User avatar
SVaidyaraman
Joined: 17 Dec 2012
Last visit: 11 Jul 2025
Posts: 566
Own Kudos:
Given Kudos: 20
Location: India
Expert
Expert reply
Posts: 566
Kudos: 1,835
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rxs0005
The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam. What grade does Moe need on his final exam in order to receive the passing grade average of 60% for the class?

A. 75%
B. 82.5%
C. 85%
D. 90%
E. 92.5%

final exam grade = f
other exam grade = 45
overall required grade = 60

40% of f= 4f/10
60% of 45=27

relationship:

27 + 4f/10=60
=>f=(600-270)/4 = 82.5
User avatar
Basshead
Joined: 09 Jan 2020
Last visit: 07 Feb 2024
Posts: 905
Own Kudos:
323
 [1]
Given Kudos: 431
Location: United States
Posts: 905
Kudos: 323
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
45% of 60 = 27

To achieve a 60, he needs at least 33 on the final.

33 of 40 = 33 * 2.5 = 82.5%
User avatar
patilpranjakt
Joined: 07 May 2019
Last visit: 30 Nov 2022
Posts: 1
Given Kudos: 2
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
i am not able to understand the question itself. can someone explain what the question is asking?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,057
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,057
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
patilpranjakt
i am not able to understand the question itself. can someone explain what the question is asking?

Hi patilpranjakt,

The wording of this prompt is a bit 'quirky', but it ultimately describes a Weighted Average.

We're told that a student's final GRADE is made up of 2 components: a final EXAM (40% of the final GRADE) and everything that came before the final EXAM (the remaining 60% of the final GRADE).

Currently, the student has a 45% average score on his assignments (re: the 60% of the final GRADE) and we are asked to figure out how high he must score on the final EXAM to raise this overall average from 45% to 60%.

There are a number of different ways to approach this prompt - and you can read about them throughout this thread.

GMAT assassins aren't born, they're made,
Rich

Contact Rich at: [email protected]
User avatar
wasario
Joined: 05 Jan 2022
Last visit: 17 Apr 2026
Posts: 54
Own Kudos:
Given Kudos: 17
Posts: 54
Kudos: 68
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For whatever reason, this problem took me over 10 minutes to even understand how to do, so I'm just leaving my own explanation to help myself in the future:

Right now, we know that 40% of the class is weighted as the finals; therefore, 60% of the class is everything outside of the finals. Right now, Moe has a score of 45 in the class before the final, and he needs to get a 60% at the end of the class (this is a different 60 from the weight 60). Thus, we can come up with an equation:

\(60 = .4f + .6(45)\) where \(f\) is the final exam score

Solving this is now just basic algebra so let's do that:

\(60 = .4f + 27\)
\(.4f = 33\)
\(f = 82.5\)

Answer choice B
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,996
Own Kudos:
Posts: 38,996
Kudos: 1,120
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
   1   2 
Moderators:
Math Expert
109975 posts
Tuck School Moderator
852 posts