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The following table shows the price of a plane ticket for an April 1st
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Bunuel
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The following table shows the price of a plane ticket for an April 1st [#permalink] New post  27 May 2018, 11:10
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A
B
C
D
E

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15% (low)

Question Stats:

91% (02:09) correct 9% (01:50) wrong based on 64 sessions

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The following table shows the price of a plane ticket for an April 1st flight, based on the date of purchase.

Image

Harpreet purchased a ticket on March 1st. If he had purchased the ticket on March 2nd, he would have paid x percent more. If he had purchased the ticket on March 16th, he would have paid y percent more than he would have paid on March 2nd. What is the positive difference between x and y?

(A) 5

(B) 14

(C) 20

(D) 25

(E) 28


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u1983
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Re: The following table shows the price of a plane ticket for an April 1st [#permalink] New post  27 May 2018, 17:54
Bunuel wrote:
The following table shows the price of a plane ticket for an April 1st flight, based on the date of purchase.

Image

Harpreet purchased a ticket on March 1st. If he had purchased the ticket on March 2nd, he would have paid x percent more. If he had purchased the ticket on March 16th, he would have paid y percent more than he would have paid on March 2nd. What is the positive difference between x and y?

(A) 5

(B) 14

(C) 20

(D) 25

(E) 28


Show Spoiler
Attachment:
chart3.jpg

Ticket price percentage increase on March 02 when compared to March 01 = \(\frac{(168-140)}{140}\)*\(100\)= \(\frac{28}{140}\)*\(100\) =\(20\)% =\(x\)
Ticket price percentage increase on March 16 when compared to March 02 = \(\frac{(210-168)}{168}\)*\(100\)= \(\frac{42}{168}\)*\(100\) =\(25\)% =\(y\)
Hence , The positive difference between x & y = \(25-20\) =\(5\)%
Hence I would go for option A.
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EgmatQuantExpert
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Posts: 3644
Re: The following table shows the price of a plane ticket for an April 1st [#permalink] New post  27 May 2018, 23:24
Expert Reply

Solution



Given:
    • Price of ticket on March 1 = $140
    • Price of ticket on March 2 = $168
    • Price of ticket on March 16 = $210
    • March 2 ticket price is more than March 1 ticket price by x%
    • March 16 ticket price is more than March 2 ticket price by y%

To find:
    • The positive difference between x and y

Approach and Working:
    • The percentage by which March 2 ticket price is more than March 1 ticket price = x = \(\frac{168 – 140}{140} * 100 = \frac{28}{140} * 100\) = 20%
    • The percentage by which March 16 ticket price is more than March 2 ticket price = y = \(\frac{210 – 168}{168} * 100 = \frac{42}{168} * 100\) = 25%
    • Therefore, the positive difference of x and y = 25 – 20 = 5

Hence, the correct answer is option A.

Answer: A
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