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22 Feb 2018, 21:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
86% (01:29) correct
14%
(01:49)
wrong
based on 118
sessions
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The formula for calculating the final velocity of a body, initially at rest, that undergoes a constant acceleration is v^2 = 2ad; where v is final velocity, a is acceleration, and d is distance traveled. If a body initially at rest is subjected to a constant acceleration of 10 meters/second^2 until it reaches a velocity of 20 meters/second, how far, expressed in meters, has the body traveled?
(A) 200
(B) 100
(C) 40
(D) 20
(E) 10
(A) 200
(B) 100
(C) 40
(D) 20
(E) 10
22 Feb 2018, 23:15
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Bunuel
Substituting the values in the equation, we get the solution to this problem
Given:
\(v^2 = 2ad\) -> \(d = \frac{v^2}{2a}\)
Here, v = 20 and a = 10
Therefore, the distance can be calculated using the formula \(\frac{v^2}{2a} = \frac{400}{2*10} = \frac{400}{20} =\)20(Option D)
23 Feb 2018, 00:49
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Bunuel
We'll show a complementary approach to the above, useful especially if you get lost in the wordiness of the question.
This is an Alternative approach and uses the answers.
Let's say the median answer, (C), is correct.
Then v^2 = 2*a*d = 2*10*40 = 800 meaning that v is the square root of 800, more than 20.
Too much! Since (C) gave too large of an answer, we'll look for a smaller option.
Say (D) was correct. Then v^2 = 2*10*20 = 400 and v=20, as required.
(D) is our answer.
