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08 Apr 2024, 08:09
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Dropdown 1: A
Dropdown 2: 12.5
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
66% (02:34) correct
34%
(02:41)
wrong
based on 1067
sessions
History
Date
Time
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Not Attempted Yet
%20at%20six%20locations%20(1).png)
The graph above shows rainfall (in mm) for May, June, and July 2022 at six locations (A to F).
Based on the graph above, June accounts for the majority of the total rainfall over the three months at location , and the rainfall at that location in June represents percent of the total rainfall across all six locations for that month.
Attachment:
Rainfall(in mm) at six locations (1).png [ 16.9 KiB | Viewed 8338 times ]
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Official Answer
Dropdown 1: A
Dropdown 2: 12.5
27 Jan 2025, 03:13
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Bunuel
Official Solution:
Drop-down 1:
Majority means more than 50%. To identify the location where June accounts for the majority of the rainfall, look for the location with a blue column longer than the combined lengths of the other two columns. At location A, the blue column is 100 mm, while the other two columns (May and July) are 25 mm and 50 mm, respectively. Since 100 mm is greater than the combined total of 75 mm, location A meets the criterion.
Drop-down 2:
Next, calculate the percentage of location A's rainfall in June relative to the total rainfall across all six locations in June. Add the lengths of the blue columns for all six locations, which total 800 mm. Location A's rainfall in June is 100 mm, so 100/800 = 12.5%. Therefore, location A's rainfall in June represents 12.5% of the total rainfall across all six locations in June.
Correct answer:
Dropdown 1: "A"
Dropdown 2: "12.5"
30 Jan 2025, 20:10
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1. Let's calculate the percentage of rainfall in each location that comes from June and see which are greater than 50% (which is majority).
- Location A. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{100}{25 + 100 + 50} \approx 0.571 = 57.1\% > 50\%\).
- Location B. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{75 + 150 + 75} = 0.5 = 50\% = 50\%\).
- Location C. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{75}{100 + 75 + 150} \approx 0.231 = 23.1\% < 50\%\).
- Location D. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{125}{100 + 125 + 75} \approx 0.417 = 41.7\% < 50\%\).
- Location E. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{100 + 150 + 75} \approx 0.462 = 46.2\% < 50\%\).
- Location F. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{200}{50 + 200 + 175} \approx 0.471 = 47.1\% < 50\%\).
Location A works.
2. In total, the amount of rain that came in June is equal to 100 + 150 + 75 + 125 + 150 + 200 = 800. The percentage of that which comes from location A is \(\frac{100}{800} = 12.5\%\).
3. Our answer will be: D1 - A and D2 - 12.5.
- Location A. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{100}{25 + 100 + 50} \approx 0.571 = 57.1\% > 50\%\).
- Location B. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{75 + 150 + 75} = 0.5 = 50\% = 50\%\).
- Location C. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{75}{100 + 75 + 150} \approx 0.231 = 23.1\% < 50\%\).
- Location D. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{125}{100 + 125 + 75} \approx 0.417 = 41.7\% < 50\%\).
- Location E. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{150}{100 + 150 + 75} \approx 0.462 = 46.2\% < 50\%\).
- Location F. \(\frac{Rainfall \ from \ June}{Total \ rainfall} = \frac{200}{50 + 200 + 175} \approx 0.471 = 47.1\% < 50\%\).
Location A works.
2. In total, the amount of rain that came in June is equal to 100 + 150 + 75 + 125 + 150 + 200 = 800. The percentage of that which comes from location A is \(\frac{100}{800} = 12.5\%\).
3. Our answer will be: D1 - A and D2 - 12.5.
