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05 Apr 2006, 12:24
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The graph of
y = | x - 2 | -1
divides the area formed by the equation
y^2 + x^2 + 2y - 4x = 4
in two parts.
What's the ratio of the smaller part to the bigger part?
y = | x - 2 | -1
divides the area formed by the equation
y^2 + x^2 + 2y - 4x = 4
in two parts.
What's the ratio of the smaller part to the bigger part?
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05 Apr 2006, 16:36
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I will go for 1:2
Its a SWAG but heres my attempt
y^2 + x^2 + 2y - 4x = 4 represents a circle
(x-2)^2 + (y+1)^2 = 9 (added 5 on each side)
So the centre of teh circle is (2,-1) and the radius is 3
Circle general eq is (x-a)^2 +(y-b)^2 = r^2
where (a,b) is the centre and r is the radius
Now take the other eq y = | x - 2 | -1
=> (y+1)^2 = (x-2)^2
Squaring both sides
y^2 + 2y + 1 = x^2 +4x +4
Taeke this and substituet in the 1st circle......
Its a SWAG but heres my attempt
y^2 + x^2 + 2y - 4x = 4 represents a circle
(x-2)^2 + (y+1)^2 = 9 (added 5 on each side)
So the centre of teh circle is (2,-1) and the radius is 3
Circle general eq is (x-a)^2 +(y-b)^2 = r^2
where (a,b) is the centre and r is the radius
Now take the other eq y = | x - 2 | -1
=> (y+1)^2 = (x-2)^2
Squaring both sides
y^2 + 2y + 1 = x^2 +4x +4
Taeke this and substituet in the 1st circle......
05 Apr 2006, 19:26
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I think it should be 1:3
y = |x-2|-1 slices away a Quarter of the circle (x-2)^2+(y+1)^2 = 9.. But this Q is
I don't think we will see such Qs on GMAT..
y = |x-2|-1 slices away a Quarter of the circle (x-2)^2+(y+1)^2 = 9.. But this Q is
I don't think we will see such Qs on GMAT..
so passsssssssssssssssss. 
