imaityaroy
Hi Experts
I have the same doubt as Srisk and umangshah. Can you please make me understand how
Q1 = S1 + A1
Q2 = S2+A2....and so on ?
Are we assuming n=k?
Why cant Q1 = S1 + A2 or any other combination?
I agree sum of digits will be equal to 9 when we add S9 and A9
n+k =18 is the maximum value when we assume n=k
if n != k then does the above still hold true ? Is it too complicated to try out in under 2 mins ?
If the question had given n = k then the picture must have been clearer
Thanks
imaityaroy Looking at your doubt, I can see you're overthinking the problem setup! Let me clarify this critical point that's causing confusion.
Key Clarification: k and n are INDEPENDENT variablesYou're absolutely right to question this! The problem states that \(q\) is the sum of \(S_k\) and \(A_n\), where
k and n can be ANY positive integers (with the constraint that \(A_n\) must be positive). The problem does
NOT require \(n = k\).
Why the confusion?The problem asks for the
maximum value of \(k + n\) when the digit sum of \(q = S_k + A_n\) equals \(9\). You can choose ANY combination like:
- \(q = S_1 + A_8\)
- \(q = S_2 + A_7\)
- \(q = S_3 + A_6\)
- ...and so on
The Strategic InsightLet's examine what happens with \(k = n = 9\):
- \(S_9 = 123456789\) (digits \(1\) through \(9\) in sequence)
- \(A_9 = 987654321\) (digits \(9\) through \(1\) in reverse)
- \(q = 123456789 + 987654321 = 1111111110\)
- Sum of digits = \(1+1+1+1+1+1+1+1+1+0 = 9\) ✓
This gives us \(k + n = 9 + 9 = 18\).
Could we get a higher sum with different k and n?No! Here's why:
- If either \(k > 9\) or \(n > 9\), we'd need \(k + n > 18\) to potentially beat our answer
- But when \(n > 9\), the sequence \(A_n\) starts including \(0\) and negative differences, making the pattern complex
- When \(k > 9\), \(S_k\) requires multi-digit endings (like \(...10, 11, 12\)), disrupting the clean digit pattern
Testing other combinations quickly:You could try \(k = 1, n = 17\) to get \(k + n = 18\), but:
- \(S_1 = 1\)
- \(A_{17}\) would have a complex pattern that likely doesn't give digit sum \(9\) when added to \(1\)
Time Management Tip:The GMAT gives you this specific setup (\(S_k\) building \(123...k\) and \(A_n\) building \(987...()\)) precisely because when \(k = n = 9\), you get the beautiful result \(1111111110\). Once you spot this pattern, you can confidently choose \(18\) without checking all possibilities.
Answer: The maximum value is
(E) 18, achieved when \(k = n = 9\), though the problem allows any valid \((k, n)\) pair.