Last visit was: 21 Apr 2026, 02:46 It is currently 21 Apr 2026, 02:46
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
enigma123
Joined: 25 Jun 2011
Last visit: 16 Mar 2016
Posts: 392
Own Kudos:
19,842
 [48]
Given Kudos: 217
Status:Finally Done. Admitted in Kellogg for 2015 intake
Location: United Kingdom
Concentration: International Business, Strategy
GMAT 1: 730 Q49 V45
GPA: 2.9
WE:Information Technology (Consulting)
GMAT 1: 730 Q49 V45
Posts: 392
Kudos: 19,842
 [48]
5
Kudos
Add Kudos
43
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,716
Own Kudos:
Given Kudos: 105,795
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,716
Kudos: 810,347
 [17]
9
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
General Discussion
avatar
Srisk
Joined: 03 Sep 2017
Last visit: 15 Dec 2017
Posts: 2
Own Kudos:
1
 [1]
Given Kudos: 10
Posts: 2
Kudos: 1
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
anvesharma
Joined: 16 Jul 2017
Last visit: 23 Aug 2022
Posts: 3
Own Kudos:
Given Kudos: 7
Posts: 3
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
enigma123
The infinite sequence Sk is defined as Sk = 10 Sk – 1 + k, for all k > 1. The infinite sequence An is defined as An = 10 An – 1 + (A1 – (n - 1)), for all n > 1. q is the sum of Sk and An. If S1 = 1 and A1 = 9, and if An is positive, what is the maximum value of k + n when the sum of the digits of q is equal to 9?
(A) 6
(B) 9
(C) 12
(D) 16
(E) 18

Guys - any idea how to solve this? I am really struggling without the OA. Therefore your help will be very much appreciated.

For such kind of sequence problems when the formula of \(n_{th}\) term is given it's almost always a good idea to write down first few terms.

Given: \(S_k=10*S_{k-1}+k\) and \(A_n=10*A_{n-1}+A_1-(n-1)\);
\(S_1=1\) and \(A_1=9\);
\(S_2=10*1+2=12\) and \(A_2=10*9+9-(2-1)=98\);
\(S_3=10*12+3=123\) and \(A_3=10*98+9-(3-1)=987\);

\(Q_1=S_1+A_1=1+9=10\) - the sum of the digit of Q is 1;
\(Q_2=S_2+A_2=12+98=110\) - the sum of the digit of Q is 2;
\(Q_3=S_1+A_3=123+987=1,110\) - the sum of the digit of Q is 3;
...

We can see the pattern in \(Q_n\): the sum of its digit equals to \(n\) itself. So the first Q for which the sum of its digit is multiple of 9 is for \(Q_9=S_9+A_9\) --> sum of the digits of \(Q_9\) is 9 --> \(k+n=9+9=18\).

Answer: E.

P.S. I wonder whether the question supposed to ask the minimum value of k + n when the sum of the digits of q is equal to 9, though anyway as 18 is the the largest value from among the answer choices it's still the right one.


The minimum value of k+n should be 9. A1+S2=21, A2+S3=221, A3+S4=2221 and A4+S5=22221. So min value of k+n =9. This would also have been the correct answer choice had the question additionally mentioned that n is even.
avatar
anvesharma
Joined: 16 Jul 2017
Last visit: 23 Aug 2022
Posts: 3
Own Kudos:
Given Kudos: 7
Posts: 3
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Srisk
Hello Bunuel,

Thanks for the detailed explanation.

Just one doubt wrt this qn. In the qn it states "q is the sum of Sk and An". Nowhere does it say n=k. Thus, q1 could also be a1+s2, correct?
Your solution is based on the assumption that n=k. Do help me understand the qn better in case I am missing something.

Thanks.

You're right, it's nowhere mentioned that n=k. Even if it weren't, the correct answer is still 18.
User avatar
umangshah
Joined: 24 May 2023
Last visit: 18 Mar 2024
Posts: 67
Own Kudos:
97
 [2]
Given Kudos: 107
Status:Preparing for Exams
Location: India
GMAT 1: 640 Q44 V34
GPA: 4
WE:Consulting (Consulting)
GMAT 1: 640 Q44 V34
Posts: 67
Kudos: 97
 [2]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Srisk
Hello Bunuel,

Thanks for the detailed explanation.

Just one doubt wrt this qn. In the qn it states "q is the sum of Sk and An". Nowhere does it say n=k. Thus, q1 could also be a1+s2, correct?
Your solution is based on the assumption that n=k. Do help me understand the qn better in case I am missing something.

Thanks.

Hello Bunuel,

Can you clear the above. I too have the same doubt. It is true that we can solve the problem by assuming n=k, but i suppose there's also got to be a way without doing that. Please share you opinion on this.

thanks
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 20 Apr 2026
Posts: 5,985
Own Kudos:
Given Kudos: 163
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,985
Kudos: 5,855
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The infinite sequence \(S_k\) is defined as \(S_k=10*S_{k-1}+k\), for all k > 1. The infinite sequence \(A_n\) is defined as \(A_n=10*A_{n-1}+A_1-(n-1)\), for all n > 1. q is the sum of \(S_k\) and \(A_n\).

If \(S_1 = 1\) and \(A_1 = 9\), and if \(A_n\) is positive, what is the maximum value of k + n when the sum of the digits of q is equal to 9?

S_9 = 123456789; A_9 = 987654321; q = S_9 + A_9 = 1111111110; k+n = 9+9 = 18

IMO E
User avatar
imaityaroy
Joined: 18 Nov 2020
Last visit: 20 Apr 2026
Posts: 18
Own Kudos:
Given Kudos: 26
Posts: 18
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Experts
I have the same doubt as Srisk and umangshah. Can you please make me understand how
Q1 = S1 + A1
Q2 = S2+A2....and so on ?

Are we assuming n=k?

Why cant Q1 = S1 + A2 or any other combination?

I agree sum of digits will be equal to 9 when we add S9 and A9
n+k =18 is the maximum value when we assume n=k
if n != k then does the above still hold true ? Is it too complicated to try out in under 2 mins ?

If the question had given n = k then the picture must have been clearer

Thanks
umangshah


Hello Bunuel,

Can you clear the above. I too have the same doubt. It is true that we can solve the problem by assuming n=k, but i suppose there's also got to be a way without doing that. Please share you opinion on this.

thanks
User avatar
egmat
User avatar
e-GMAT Representative
Joined: 02 Nov 2011
Last visit: 11 Apr 2026
Posts: 5,632
Own Kudos:
33,428
 [1]
Given Kudos: 707
GMAT Date: 08-19-2020
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 5,632
Kudos: 33,428
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
imaityaroy
Hi Experts
I have the same doubt as Srisk and umangshah. Can you please make me understand how
Q1 = S1 + A1
Q2 = S2+A2....and so on ?

Are we assuming n=k?

Why cant Q1 = S1 + A2 or any other combination?

I agree sum of digits will be equal to 9 when we add S9 and A9
n+k =18 is the maximum value when we assume n=k
if n != k then does the above still hold true ? Is it too complicated to try out in under 2 mins ?

If the question had given n = k then the picture must have been clearer

Thanks

imaityaroy

Looking at your doubt, I can see you're overthinking the problem setup! Let me clarify this critical point that's causing confusion.

Key Clarification: k and n are INDEPENDENT variables

You're absolutely right to question this! The problem states that \(q\) is the sum of \(S_k\) and \(A_n\), where k and n can be ANY positive integers (with the constraint that \(A_n\) must be positive). The problem does NOT require \(n = k\).

Why the confusion?
The problem asks for the maximum value of \(k + n\) when the digit sum of \(q = S_k + A_n\) equals \(9\). You can choose ANY combination like:
  • \(q = S_1 + A_8\)
  • \(q = S_2 + A_7\)
  • \(q = S_3 + A_6\)
  • ...and so on

The Strategic Insight
Let's examine what happens with \(k = n = 9\):
  • \(S_9 = 123456789\) (digits \(1\) through \(9\) in sequence)
  • \(A_9 = 987654321\) (digits \(9\) through \(1\) in reverse)
  • \(q = 123456789 + 987654321 = 1111111110\)
  • Sum of digits = \(1+1+1+1+1+1+1+1+1+0 = 9\) ✓

This gives us \(k + n = 9 + 9 = 18\).

Could we get a higher sum with different k and n?
No! Here's why:
  1. If either \(k > 9\) or \(n > 9\), we'd need \(k + n > 18\) to potentially beat our answer
  2. But when \(n > 9\), the sequence \(A_n\) starts including \(0\) and negative differences, making the pattern complex
  3. When \(k > 9\), \(S_k\) requires multi-digit endings (like \(...10, 11, 12\)), disrupting the clean digit pattern

Testing other combinations quickly:
You could try \(k = 1, n = 17\) to get \(k + n = 18\), but:
  • \(S_1 = 1\)
  • \(A_{17}\) would have a complex pattern that likely doesn't give digit sum \(9\) when added to \(1\)

Time Management Tip:
The GMAT gives you this specific setup (\(S_k\) building \(123...k\) and \(A_n\) building \(987...()\)) precisely because when \(k = n = 9\), you get the beautiful result \(1111111110\). Once you spot this pattern, you can confidently choose \(18\) without checking all possibilities.

Answer: The maximum value is (E) 18, achieved when \(k = n = 9\), though the problem allows any valid \((k, n)\) pair.
Moderators:
Math Expert
109716 posts
Tuck School Moderator
853 posts