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Chasingthesun
total no of outcomes = 25
favourable outcomes = 4 i.e (5,5,5 / 5,5,4 / 5,4,4 / 5,5,3)

IMO ans D


I am sorry,I was probably sleeping when I wrote this
Horrible mistake :cry: :cry:

Total no of outcomes : 5^3
Fav outcomes : 10

Total possibilities : 10/5^3 = 2/25 ans B

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Correct Option B

Replacement : Multiplication with same possibility
Not Replacement : Factorization with same possibility.

Here possibility : 3, with replacement : 5*5*5 = 125

Condition 2: Sum must be in range {13 to 15} from numbers 1,2,3,4,5 named on the cards.
Possibility 1 : 555
Possibility 3 : 554, 545, 455
Possibility 6 : 543, 534, 435, 453, 345, 354
Total : 10
Probability sum {13 to 15} = 10/125 = 2/25 is option B

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Chasingthesun
total no of outcomes = 25
favourable outcomes = 4 i.e (5,5,5 / 5,5,4 / 5,4,4 / 5,5,3)

IMO ans D
hi,
shouldn't the total outcomes be 125
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Chasingthesun
total no of outcomes = 25
favourable outcomes = 4 i.e (5,5,5 / 5,5,4 / 5,4,4 / 5,5,3)

IMO ans D
hi,
shouldn't the total outcomes be 125


that's right. I don't know what I was thinking when I wrote 25 :( :dazed
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The integers 1 through 5 are written on each of five cards. The cards are shuffled and one card is drawn at random. That card is then replaced, the cards are shuffled again and another card is drawn at random. This procedure is repeated one more time (for a total of three times). What is the probability that the sum of the numbers on the three cards drawn was between 13 and 15, inclusive?

A. 1/25
B. 2/25
C. 3/25
D. 4/25
E. 1/5



This question is a part of Are You Up For the Challenge: 700 Level Questions collection.
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