suyash23n wrote:

The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs $1 per pack and brand B costs $1.5 per pack. Last week , brand A contributed to m% of stall’s revenue and accounted for n% of sales of juice tetra packs. Which of the following expresses m in terms of n?

(A) 100n/(150 – n)

(B) 200n/(250-n)

(C) 200n/(300-n)

(D) 250n/(400-n)

(E) 300n/(500-n)

Let´s explore an

AGGRESSIVE PARTICULAR CASE:

n = 100 : in this case, only brand A was sold, hence all revenue came from brand A and our

FOCUS will be (the

TARGET) m =100 (of course)!

\(\left. \begin{gathered}

\left( A \right)\,\,\,\frac{{{{10}^4}}}{{50}} \ne 100 \hfill \\

\left( B \right)\,\,\frac{{2 \cdot {{10}^4}}}{{150}} \ne 100 \hfill \\

\left( C \right)\,\,\frac{{2 \cdot {{10}^4}}}{{200}} = 100\,\,\,\,\, \hfill \\

\left( D \right)\,\,\frac{{25 \cdot {{10}^3}}}{{300}} \ne 100 \hfill \\

\left( E \right)\,\,\frac{{3 \cdot {{10}^4}}}{{400}} \ne 100 \hfill \\

\end{gathered} \right\}\,\,\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{{\text{only}}\,\,{\text{survivor}}\,{\text{!}}} \,\,\,\,\,\,\,\left( C \right)\)

This solution follows the notations and rationale taught in the GMATH method.

Regards,

Fabio.

_________________

Fabio Skilnik :: GMATH method creator (Math for the GMAT)

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