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The larger of two consecutive odd integers is three times the smaller.

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The larger of two consecutive odd integers is three times the smaller.  [#permalink]

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New post 14 Mar 2019, 01:48
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The larger of two consecutive odd integers is three times the smaller. What is their sum?

(A) 4
(B) 8
(C) 12
(D) 16
(E) 20
Spoiler: OA

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Re: The larger of two consecutive odd integers is three times the smaller.  [#permalink]

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New post 14 Mar 2019, 03:14
Bunuel wrote:
The larger of two consecutive odd integers is three times the smaller. What is their sum?

(A) 4
(B) 8
(C) 12
(D) 16
(E) 20



Consecutive odd integers.

Smaller = x

Larger = x + 2


As per the question:

x + 2 = 3x

x = 1.

and

x + 2 = 3.

Sum: x + x + 2 = 1 + 3 = 4.

A is the correct answer.
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Re: The larger of two consecutive odd integers is three times the smaller.  [#permalink]

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New post 14 Mar 2019, 04:56
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Bunuel wrote:
The larger of two consecutive odd integers is three times the smaller. What is their sum?

(A) 4
(B) 8
(C) 12
(D) 16
(E) 20



n+n+2
so
n+2=3n
n=1
sum
4
IMO A
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Re: The larger of two consecutive odd integers is three times the smaller.  [#permalink]

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New post 18 Mar 2019, 18:51
Bunuel wrote:
The larger of two consecutive odd integers is three times the smaller. What is their sum?

(A) 4
(B) 8
(C) 12
(D) 16
(E) 20


Let x = the smaller odd integer; then (x + 2) = the larger odd integer. We can create the equation:

x + 2 = 3x

2 = 2x

x = 1

The smaller integer is 1 so the larger integer is 3, and the sum of the two integers is 1 + 3 = 4.

Answer: A
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Re: The larger of two consecutive odd integers is three times the smaller.   [#permalink] 18 Mar 2019, 18:51
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