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11 Sep 2020, 23:18
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Please see attached picture.
Can someone just explain to me why you ditch the 12 when trying to get the root out of the bottom. This is my first time seeing this and I am pretty deep into quant studying, which obviously isn't good.
Does this apply to all denominators with the root of a number and a preceding integer? I know for binomials we flip the sign and still use the whole denominator equation to get rid of the root.
Thanks for the help.
Can someone just explain to me why you ditch the 12 when trying to get the root out of the bottom. This is my first time seeing this and I am pretty deep into quant studying, which obviously isn't good.
Does this apply to all denominators with the root of a number and a preceding integer? I know for binomials we flip the sign and still use the whole denominator equation to get rid of the root.
Thanks for the help.
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Can someone just explain to me why you ditch the 12
Its because this makes equation easier to solve if want to solve 25/12*3^(1/2) this by multiplying 12*3^(1/2) to both numerator and denominator you can also do that but that makes calculation lengthy (takes more time to solve) that's why we only multiply 3^(1/2) to both numerator and denominator to get root from denominator.
Its because this makes equation easier to solve if want to solve 25/12*3^(1/2) this by multiplying 12*3^(1/2) to both numerator and denominator you can also do that but that makes calculation lengthy (takes more time to solve) that's why we only multiply 3^(1/2) to both numerator and denominator to get root from denominator.
12 Sep 2020, 09:56
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Loser94
Thank you. So essentially if there is a single integer multiplying to the (or any other root) \(\sqrt{3}\), we can just ditch the preceding integer? I did exponents and roots so long ago at this point, I need to go back through my flashcards.
Appreciate the help, stranger!
