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28 Jul 2017, 09:07
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:35) correct
28%
(01:28)
wrong
based on 334
sessions
History
Date
Time
Result
Not Attempted Yet
The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
29 Jul 2017, 09:32
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Bunuel
The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
Solution
- • Let the numbers be \(n-12,n-11,…………. , n, ,………….n+11,n+12\)
- o The mean of the above would be \(= n\)
o The sum of 25 numbers will be \(= 25n\)
o Thus, the percentage \(= n*\frac{100}{25n} = 4\)%
Thanks,
Saquib
Quant Expert
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[/url General Discussion
28 Jul 2017, 09:54
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Bunuel
The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
let the consecutive numbers be from 1 to 25
Sum = \(\frac{n}{2}*(first term + last term) =\) \(\frac{25}{2}*(1+25)\)
or Sum = 25*13
Therefore Mean of 25 terms will be = \(\frac{25*13}{25}\) = 13
so Mean as % of Sum = \(\frac{13}{(25*13)}*100\) = 4%
Option A
