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The mean of twenty-five consecutive positive integers numbers is what
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28 Jul 2017, 08:54
3
Bunuel wrote:
The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
let the consecutive numbers be from 1 to 25 Sum = \(\frac{n}{2}*(first term + last term) =\) \(\frac{25}{2}*(1+25)\) or Sum = 25*13 Therefore Mean of 25 terms will be = \(\frac{25*13}{25}\) = 13 so Mean as % of Sum = \(\frac{13}{(25*13)}*100\) = 4% Option A
Re: The mean of twenty-five consecutive positive integers numbers is what
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28 Jul 2017, 09:09
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I assume when the question says "total" it means to say "sum". By definition, mean = sum/n, where n is the number of terms.
We have n = 25, so:
mean = sum / 25
so the mean is 1/25 of the sum, or 4% of the sum.
It's not important that the set consists of consecutive integers.
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Re: The mean of twenty-five consecutive positive integers numbers is what
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29 Jul 2017, 08:41
1
IanStewart wrote:
I assume when the question says "total" it means to say "sum". By definition, mean = sum/n, where n is the number of terms.
We have n = 25, so:
mean = sum / 25
so the mean is 1/25 of the sum or 4% of the sum.
It's not important that the set consists of consecutive integers.
I guess this would be the best way to solve it. If we focus on the definition, we can indeed come to conclusion that the relation between Mean and Sum is -
Mean/Sum = 1/N, where N is the total number of terms.
With this inference in mind, it would hardly take any time to solve this question.
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Re: The mean of twenty-five consecutive positive integers numbers is what
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10 Nov 2017, 16:05
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Top Contributor
Bunuel wrote:
The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
----------ASIDE---------------------- There's a nice rule that says, "In a set where the numbers are equally spaced, the mean will equal the median." For example, in each of the following sets, the mean and median are equal: {7, 9, 11, 13, 15} {-1, 4, 9, 14} {3, 4, 5, 6} ------------------ For this question, let x = first value So, x+1 = second value x+2 = third value . . . x+24 = last value
This means x+12 is the median AND the mode
Since x+12 = the mean of the 25 numbers, we can conclude that (25)(x+12 ) = the SUM of the 25 numbers
The mean of twenty-five consecutive positive integers numbers is what percent of the total? We must convert (x+12)/(25)(x+12) to a PERCENT (x+12)/(25)(x+12) = 1/25 = 4/100 = 4% Answer: A
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78% (01:36) correct 
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