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# The nth term (tn) of a certain sequence is defined as tn = t(n-1) + 4

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The nth term (tn) of a certain sequence is defined as tn = t(n-1) + 4 [#permalink]
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Here is another way:

Given: T1 = Tn-1 +4 & T1 = -7

Then solve to get the
Direct Formula:
Tn = k*n+x k is the constant change which is 4 in this problem, find x

T1 = k + x
T1: -7 = 4 + x
x = -11

Tn= 4*n -11

Use this formula to find T71:
T71= 4*(71) -11
= 284 - 11
= 273
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Re: The nth term (tn) of a certain sequence is defined as tn = t(n-1) + 4 [#permalink]
shrive555 wrote:
The nth term (tn) of a certain sequence is defined as
tn = tn-1 + 4. If t1= -7 then t71 =

OA=273

I see you are working with sequences and series today. The story I wrote in response to your previous question will work perfectly well here too since this is an arithmetic progression too. If you understand it, you will get this question on your own. Go back and read it again and try this question again. If you don't get it, let me know what you don't understand in the theory.
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Re: The nth term (tn) of a certain sequence is defined as tn = t(n-1) + 4 [#permalink]
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Re: The nth term (tn) of a certain sequence is defined as tn = t(n-1) + 4 [#permalink]
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