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The nth terms of the two series are equal, then the value of n is

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The nth terms of the two series are equal, then the value of n is  [#permalink]

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New post Updated on: 03 Feb 2019, 01:54
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A
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C
D
E

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67% (00:45) correct 33% (00:40) wrong based on 10 sessions

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The nth terms of the two series are equal, then the value of n is

(1) The first series is 3 + 10 + 17 + ...
(2) The second series is 63 + 65 + 67 + ……

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Originally posted by 4d on 02 Feb 2019, 20:06.
Last edited by Bunuel on 03 Feb 2019, 01:54, edited 1 time in total.
Renamed the topic and edited the question.
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Re: The nth terms of the two series are equal, then the value of n is  [#permalink]

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New post 02 Feb 2019, 22:39
4d wrote:
The \(nth\) terms of the two series are equal, then the value of \(n\) is
1) The first series is \(3 + 10 + 17 + …\)
2) The second series is \(63 + 65 + 67 + ……\)


nth term for first series \(3+(n-1)*7\)
nth term for second series \(63+(n-1)*2\)

nth term are equal \(3+(n-1)*7\)=\(63+(n-1)*2\)
solving n=13

option C
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Re: The nth terms of the two series are equal, then the value of n is  [#permalink]

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New post 02 Feb 2019, 23:09
As this series is continuous, there will be multiple answer for nth term so E is the answer
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Re: The nth terms of the two series are equal, then the value of n is   [#permalink] 02 Feb 2019, 23:09
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The nth terms of the two series are equal, then the value of n is

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