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The number 3,080 has how many distinct prime factors?

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The number 3,080 has how many distinct prime factors? [#permalink]

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Re: The number 3,080 has how many distinct prime factors? [#permalink]

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New post 28 Mar 2018, 03:43
3080 = 2^3*11*7*5
Number of distinct prime factors = 2,11,7 and 5
My answer :four (option c)
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The number 3,080 has how many distinct prime factors? [#permalink]

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New post Updated on: 28 Mar 2018, 05:14
3080 = 2*3 x 5 x 7 x 11.
Ans is 4.

Originally posted by Prirommy on 28 Mar 2018, 04:58.
Last edited by Prirommy on 28 Mar 2018, 05:14, edited 1 time in total.
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Re: The number 3,080 has how many distinct prime factors? [#permalink]

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New post 28 Mar 2018, 05:10
Prirommy wrote:
3080 = 2*4 x 5 x 7 x 11.
Ans is 4.


Its not 2^4 , its ^3
typo error.. i guess
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Re: The number 3,080 has how many distinct prime factors? [#permalink]

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New post 28 Mar 2018, 23:07
Factors of 3080 are: \(2^3\)*5*7*11

No of distinct factors are: 2, 5, 7, 11

\(Answer: C.\)
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Re: The number 3,080 has how many distinct prime factors? [#permalink]

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New post 29 Mar 2018, 17:18
Bunuel wrote:
The number 3,080 has how many distinct prime factors?

(A) Two
(B) Three
(C) Four
(D) Five
(E) Six


We can break 3,080 into prime factors:

3,080 = 308 x 10 = 4 x 77 x 5 x 2 = 2^2 x 11 x 7 x 5 x 2 = 2^3 x 5 x 7 x 11

So 3,080 has 4 distinct prime factors.

Answer: C
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Re: The number 3,080 has how many distinct prime factors?   [#permalink] 29 Mar 2018, 17:18
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