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# The number of passengers on a certain bus at any given time

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Director
Joined: 23 May 2008
Posts: 685
The number of passengers on a certain bus at any given time  [#permalink]

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13 Sep 2008, 16:41
1
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0
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Director
Joined: 23 Sep 2007
Posts: 730

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13 Sep 2008, 16:49
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32
Director
Joined: 23 Sep 2007
Posts: 730

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13 Sep 2008, 16:54
C

the max number of passenger is at the 4th stop, at the 6th stop, there will be 24
Manager
Joined: 09 Jul 2007
Posts: 209

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13 Sep 2008, 17:01
If by 2(S – 4)2 + 32 you mean 2(S – 4)^2 + 32 .. then yes after 6 stops , the number of passenger will be 24

IMO C .
Senior Manager
Joined: 29 Mar 2008
Posts: 325

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13 Sep 2008, 17:14
(C) for me too.

Based on the formula, highest # of passenger is when s=4, i.e P=32.
2 stops after when s=4 is -> s=6. P=24 when S=6 and hence (C)
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Director
Joined: 23 May 2008
Posts: 685

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13 Sep 2008, 18:00
OA is C, sorry about the typo
VP
Joined: 17 Jun 2008
Posts: 1197

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13 Sep 2008, 23:45
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32

IMO C
4th stop max=32 ,
6th stop => 24 => IMO C
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VP
Joined: 17 Jun 2008
Posts: 1389

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15 Sep 2008, 00:42
gmatnub wrote:
bigtreezl wrote:
The number of passengers on a certain bus at any given time is given by the equation
P = -2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, how many passengers will be on the bus two stops after the stop where it has its greatest number of passengers?
32
30
24
14
0

The correct formula is P = -2(S – 4)^2 + 32

That made sense. Otherwise, with S = 0, P was not coming out to 0.

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This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Non-Human User
Joined: 09 Sep 2013
Posts: 10147
Re: The number of passengers on a certain bus at any given time  [#permalink]

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16 Feb 2019, 08:48
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The number of passengers on a certain bus at any given time   [#permalink] 16 Feb 2019, 08:48
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