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substitute the value of S so we get no of passengers from the equation

A) p= -2(9-4)*2 +32 = -18
B) p= -2(6-4)*2 +32 = 24
c) p= -2(4-4)*2 + 32 = 32
D)p= -2(1-4)*2 +32 = 14

ans is option C because it has highst number of pasngrs


in gmat we start substituting from option C which makes this problem much easier
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The negetive sign in the first part of the equation indicates that P will be the largest when (S-4)^2 =0

-> S-4 = 0
S = 4

Therefore Option C
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Prasanna675
substitute the value of S so we get no of passengers from the equation

A) p= -2(9-4)*2 +32 = -18
B) p= -2(6-4)*2 +32 = 24
c) p= -2(4-4)*2 + 32 = 32
D)p= -2(1-4)*2 +32 = 14

ans is option C because it has highst number of pasngrs


in gmat we start substituting from option C which makes this problem much easier

How does it make it any easier if we start substituting from Option C ? Won't you still need to substitute in all the OCs ?
Let me know if there is a way. it would be really helpful to minimize time.
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DhruvPatelD10
Prasanna675
substitute the value of S so we get no of passengers from the equation

A) p= -2(9-4)*2 +32 = -18
B) p= -2(6-4)*2 +32 = 24
c) p= -2(4-4)*2 + 32 = 32
D)p= -2(1-4)*2 +32 = 14

ans is option C because it has highst number of pasngrs


in gmat we start substituting from option C which makes this problem much easier

How does it make it any easier if we start substituting from Option C ? Won't you still need to substitute in all the OCs ?
Let me know if there is a way. it would be really helpful to minimize time.

I've been told the same many times by people. I think the logic behind this rule of thumb for substitution is " most tricky substitution questions have the answer hidden in the bottom 2-3"

It is natural tendency to begin with first option and hence people would burn up their time wasting effort. But again, it's just a theory! I never use substitution ( which can be another drawback - precise solutions can be time consuming themselves !)

Best,
Gladi
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