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# The numbers x and y are NOT integers. The value of x is

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The numbers x and y are NOT integers. The value of x is  [#permalink]

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Updated on: 09 Apr 2012, 12:37
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Question Stats:

62% (01:08) correct 38% (00:58) wrong based on 572 sessions

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The numbers x and y are NOT integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y
(2) 1 is the integer that is closest to x-y

Originally posted by ezinis on 04 Jan 2011, 13:52.
Last edited by Bunuel on 09 Apr 2012, 12:37, edited 1 time in total.
Edited the question
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Re: The numbers x and y are not integers ...  [#permalink]

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04 Jan 2011, 14:05
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The numbers x and y are NOT integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y --> $$3.5<x+y<4.5$$. Not sufficient.
(2) 1 is the integer that is closest to x-y --> $$0.5<x-y<1.5$$. Not sufficient.

(1)+(2) Sum above inequalities: $$4<2x<6$$ --> $$2<x<3$$ --> so $$x$$ can be closer to 2 (for example if $$x=2.1$$) as well as to 3 (for example if $$x=2.9$$). Not sufficient.

Check similar question: if-500-is-the-multiple-of-99421.html

Hope it helps.
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04 May 2011, 10:52
2
Numbers X and Y are not integers. the value of x is closest to which integer?

A. 4 is the integer that is closest to X+Y
B. 1 is the integer that is closest to X-Y

---

1) so x + y equals 3.51 to 4.49 and x can be 0.52 and close to one or could be equal 3.48 and close to 3. Insuff. AD out

2) so x - y can be equal to 0.51 or 1.49 for example and x can be 1.01 and close to 1 or x could be 0.48 and x close to 0 Insuff B out

1+2) we know 3.51 < x + y < 4.49
0.51 < x - y < 1.49

If we add both y cancels out and we get 4.02 < 2x < 5.98 and so 2.01 < x < 2.99 so x could be close to 2 or 3 Insuff

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Re: The numbers x and y are not integers ...  [#permalink]

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04 May 2011, 23:31
1+2 gives ,

2.1 < x < 2.9 thereby giving either 2 or 3 as value. Hence E.
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Re: The numbers x and y are not integers ...  [#permalink]

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07 May 2011, 15:50
1. Not sufficient

3.5<= x+y <= 4.4

we can choose different x values that satisfy the above expression

2. Not sufficient

0.5<=x-y<=1.4

we can choose different x values that satisfy the above expression

1&2
2<=x<=2.9. still not sufficient as x can be close to 2 or 3.

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Re: The numbers x and y are not integers ...  [#permalink]

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21 Nov 2011, 18:50
Bunuel wrote:
The numbers x and y are NOT integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y --> $$3.5<x+y<4.5$$. Not sufficient.
(2) 1 is the integer that is closest to x-y --> $$0.5<x-y<1.5$$. Not sufficient.

(1)+(2) Sum above inequalities: $$4<2x<6$$ --> $$2<x<3$$ --> so $$x$$ can be closer to 2 (for example if $$x=2.1$$) as well as to 3 (for example if $$x=2.9$$). Not sufficient.

Check similar question: if-500-is-the-multiple-of-99421.html

Hope it helps.

How do we know we need to take $$3.5<x+y<4.5$$ or $$3.5<=x+y<=4.5$$ ??????
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Re: The numbers x and y are not integers ...  [#permalink]

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24 Nov 2011, 22:35
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siddhans wrote:
How do we know we need to take $$3.5<x+y<4.5$$ or $$3.5<=x+y<=4.5$$ ??????

4 is the integer that is closest to x+y i.e. there is a single integer that is closest to (x+y)
If (x+y) = 3.5, which integer is closest to it? Both 3 and 4 are at equal distance i.e. they are both 0.5 away from (x+y). But then, we cannot say that 4 is the integer closest to x+y.
Hence, x+y must be greater than 3.5. It must also be less than 4.5 due to the same reason.

Note: 3.5 is rounded up to 4 instead of 3 only because we generally follow round up convention. If we follow 'round down' convention, 3.5 will be rounded off to 3.
3.5 is equidistant from both 3 and 4.
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Re: The numbers x and y are not integers ...  [#permalink]

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25 Nov 2011, 17:27
VeritasPrepKarishma wrote:
siddhans wrote:
Note: 3.5 is rounded up to 4 instead of 3 only because we generally follow round up convention. If we follow 'round down' convention, 3.5 will be rounded off to 3.
3.5 is equidistant from both 3 and 4.

If on another question, we knew that x when rounded is equal to 4 then : $$3,5\leq x <4,5$$. Correct?
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Re: The numbers x and y are not integers ...  [#permalink]

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26 Nov 2011, 05:22
If you are not good with inequalities, you can also do this with selecting values to see if you can come up with values that satisfy both 1. & 2. but give different answers for which integer x is closest to.

e.g. from 1. & 2. you can see that x is around 2.5 and y around 1.5.

if x is 2.49 and y is 1.5 you can see that both statements hold (x is closest to 2).
if x is 2.51 and y is 1.5 you can see that both statements hold (x is closest to 3).

so even together, there is INSUFFICIENT information to solve.

Same as the answers above, but a different way of approaching it.
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Re: The numbers x and y are not integers ...  [#permalink]

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04 Jan 2012, 12:26
E is the answer. The statements are insufficient individually and also when combined. The value of x is between 2 and 3 but a definite answer to a single integer cannot be obtained. Hence, INSUFFICIENT.
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Re: The numbers x and y are not integers ...  [#permalink]

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04 Jan 2012, 13:57
Clearly solving S1 and S2 does not make any sense since they could be any fractional combination.

So, it is C or E.

Together, we could have 2.5-1.5 or 2.4-1.4, both meet S1 and S2. However, 2.5 = 3 rounded and 2.4 = 2 rounded. So, insufficient

E.
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The numbers x and y are NOT integers. The value of x is closest  [#permalink]

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21 Jan 2013, 23:54
amitdgr wrote:
The numbers x and y are not integers. The value of x is closest to which integer ?

(1) 4 is the integer that is closest to x+y
(2) 1 is the integer that is closest to x-y

Statement 1:
3.5 < x+y < 4.5

We could also have multiple values of possible y
which would either give us an x closest to 0 to 4. INSUFFICIENT!

Statement 2:
0.5 < x-y < 1.5

This will also be INSUFFICIENT like Statement 1.

Together:
Let x+y = 4.4 and x-y = 1.4 ==> 2x = 3 ==> x= 1.5, closest to 2
Let x+y = 4.1 and x-y = 1.4 ==> 2x= 2.7 ==> x=1.35, closest to 1

.. and there are many more possible combinations...

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Re: The numbers x and y are NOT integers. The value of x is  [#permalink]

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05 Sep 2018, 07:51
Top Contributor
ezinis wrote:
The numbers x and y are NOT integers. The value of x is closest to which integer?

(1) 4 is the integer that is closest to x+y
(2) 1 is the integer that is closest to x-y

Target question: The value of x is closest to which integer?

Statements 1 and 2 combined
There are several values of x and y that satisfy BOTH statements. Here are two:
Case a: x = 2.4 and y = 1.4. These values satisfy both statements. In this case, the answer to the target question is 2 is the closest integer to x
Case b: x = 2.6 and y = 1.4. These values satisfy both statements. In this case, the answer to the target question is 3 is the closest integer to x
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Cheers,
Brent
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Re: The numbers x and y are NOT integers. The value of x is &nbs [#permalink] 05 Sep 2018, 07:51
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