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The only contents in a container are green disks, blue disks

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The only contents in a container are green disks, blue disks  [#permalink]

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New post 07 Jan 2014, 04:08
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The only contents in a container are green disks, blue disks, and orange disks. If one disk is selected at random from the container, what is the probability that the disk is orange?

(1) The ratio of the number of orange disks to the number of disks that are not orange is 7 to 36.

(2) The ratio of the number of green disks to the number of blue disks is 7 to 3, and the ratio of the number of green disks to the number of orange disks is 18 to 5.

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The only contents in a container are green disks, blue disks  [#permalink]

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New post 07 Jan 2014, 04:37
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The only contents in a container are green disks, blue disks, and orange disks. If one disk is selected at random from the container, what is the probability that the disk is orange?

(1) The ratio of the number of orange disks to the number of disks that are not orange is 7 to 36 --> (orange)/(not orange) = 7/36 --> (orange)/(orange + not orange) = (orange)/(total) = 7/(7 + 36) = 7/43. Sufficient.

(2) The ratio of the number of green disks to the number of blue disks is 7 to 3, and the ratio of the number of green disks to the number of orange disks is 18 to 5 --> (green)/(blue) = 7/3 = 126/54 and (green)/(orange) = 18/5 = 126/35 --> (orange)/(blue + green + orange) = 35/(54 + 126 + 35) = 7/43. Sufficient.

Answer: D.
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Re: The only contents in a container are green disks, blue disks  [#permalink]

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New post 01 Sep 2014, 20:42
Hi Bunel ... should'nt it be 126/126+35+54 ???? RATHER THAN 25/.....
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Re: The only contents in a container are green disks, blue disks  [#permalink]

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New post 01 Sep 2014, 21:46
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Re: The only contents in a container are green disks, blue disks  [#permalink]

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New post 19 Oct 2017, 11:03
Bunuel wrote:
The only contents in a container are green disks, blue disks, and orange disks. If one disk is selected at random from the container, what is the probability that the disk is orange?

(1) The ratio of the number of orange disks to the number of disks that are not orange is 7 to 36 --> (orange)/(not orange) = 7/36 --> (orange)/(orange + not orange) = (orange)/(total) = 7/(7 + 36) = 7/43. Sufficient.

(2) The ratio of the number of green disks to the number of blue disks is 7 to 3, and the ratio of the number of green disks to the number of orange disks is 18 to 5 --> (green)/(blue) = 7/3 = 126/54 and (green)/(orange) = 18/5 = 126/35 --> (orange)/(blue + green + orange) = 35/(54 + 126 + 35) = 7/43. Sufficient.

Answer: D.


Hi Bunuel,
Can you please explain how did we get 126/54 and 126/35?
(green)/(blue) = 7/3 = 126/54 and (green)/(orange) = 18/5 = 126/35
Thanks
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Re: The only contents in a container are green disks, blue disks  [#permalink]

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New post 19 Oct 2017, 11:13
lor12345 wrote:
Bunuel wrote:
The only contents in a container are green disks, blue disks, and orange disks. If one disk is selected at random from the container, what is the probability that the disk is orange?

(1) The ratio of the number of orange disks to the number of disks that are not orange is 7 to 36 --> (orange)/(not orange) = 7/36 --> (orange)/(orange + not orange) = (orange)/(total) = 7/(7 + 36) = 7/43. Sufficient.

(2) The ratio of the number of green disks to the number of blue disks is 7 to 3, and the ratio of the number of green disks to the number of orange disks is 18 to 5 --> (green)/(blue) = 7/3 = 126/54 and (green)/(orange) = 18/5 = 126/35 --> (orange)/(blue + green + orange) = 35/(54 + 126 + 35) = 7/43. Sufficient.

Answer: D.


Hi Bunuel,
Can you please explain how did we get 126/54 and 126/35?
(green)/(blue) = 7/3 = 126/54 and (green)/(orange) = 18/5 = 126/35
Thanks

In order to make ratios comparable we multiply by the common multiple of bot the ratios...so 7x18= 126
And 7x5= 35

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Re: The only contents in a container are green disks, blue disks &nbs [#permalink] 19 Oct 2017, 11:13
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