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The outline of a sign for an ice-cream store is made by

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CEO
Joined: 15 Aug 2003
Posts: 3452

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The outline of a sign for an ice-cream store is made by [#permalink]

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01 Oct 2003, 14:27
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The outline of a sign for an ice-cream store is made by placing 3/4th
of the circumference of a circle with a radius 2 feet on top of an
isoceles triangle with height 5ft..
What is the perimeter ,in feet , of the sign??

1)3pi +3root3
2)3pi +6root3
3)3pi +2root33
4)3pi - 3root3
5)4pi +6root3.

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Senior Manager
Joined: 21 Aug 2003
Posts: 257

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Location: Bangalore

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02 Oct 2003, 08:39
praet it seems u forgot to attach the ice cream sign. guess u dont wanna share ice cream with us.. just kidding..

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CEO
Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 929 [0], given: 781

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02 Oct 2003, 09:47
Vicky wrote:
praet it seems u forgot to attach the ice cream sign. guess u dont wanna share ice cream with us.. just kidding..

Nope, i didnt, there is no sign ....the problem is as is....want to try?

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Senior Manager
Joined: 22 May 2003
Posts: 328

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Location: Uruguay

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02 Oct 2003, 16:05

Total perimeter of circle=4P├н since we have 3/4 of it the perimeter of that part is 3P├н

Let us call A and B the intersection points between the circumference and the cord (base of the isosceles triangle), and O the center of the circumference.

AOB is a rectangle triangle because 1/4 of 360 is 90 degrees.

Since AO=BO it is also isosceles, so AB=2*sqrt(2)

With that and the height of the cone you can get both sides. Each side is =sqrt(2+25)=3*sqrt(3)

Total perimeter=3P├н + 3*sqrt(3) + 3*sqrt(3)=3P├н + 6*sqrt(3)

thoughts?

Martin

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Intern
Joined: 29 Aug 2003
Posts: 47

Kudos [?]: 2 [0], given: 0

Location: Detroit, MI

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09 Oct 2003, 12:17
MartinMag wrote:

Total perimeter of circle=4P├н since we have 3/4 of it the perimeter of that part is 3P├н

Let us call A and B the intersection points between the circumference and the cord (base of the isosceles triangle), and O the center of the circumference.

AOB is a rectangle triangle because 1/4 of 360 is 90 degrees.

Since AO=BO it is also isosceles, so AB=2*sqrt(2)

With that and the height of the cone you can get both sides. Each side is =sqrt(2+25)=3*sqrt(3)

Total perimeter=3P├н + 3*sqrt(3) + 3*sqrt(3)=3P├н + 6*sqrt(3)

thoughts?

Martin

Yup, that's right. It's kinda hard to visualize this without a diagram though.

Amar.

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09 Oct 2003, 12:17
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