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The outside of the rectangular box represented in the figure [#permalink]

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19 Jan 2013, 03:17

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The outside of the rectangular box represented in the figure above is to be decorated by attaching pieces of wrapping paper to cover all surfaces except the bottom of the box. what is the minimum number of sqaure inches of wrapping paper needed?

Re: The outside of the rectangular box represented in the figure [#permalink]

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19 Jan 2013, 09:52

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total area of cuboid - area of bottom of cuboid = paper required to wrap all sides except bottom of the cuboid

total area of cuboid = area of top and bottom side faces (l*b)+area of two side faces(h*b) + area of two side faces (l*h) = 2*25*10 + 2*5*10 + 2*25*5 = 500+100+250=850

area of bottom face = 250

so paper needed = 850 - 250 = 600 sqinches
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Re: The outside of the rectangular box represented in the figure [#permalink]

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01 May 2015, 02:52

even immediately after finishing reading the question, we know how to solve the problem. this one takes on more than 90 seconds to get to the correct choice. practice a lot is good
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visit my facebook to help me. on facebook, my name is: thang thang thang

Re: The outside of the rectangular box represented in the figure [#permalink]

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08 Mar 2016, 17:03

Hey All,

Its super basic but I'm having trouble in translating top/bottom/sides wording into length, width and height. As the general formula for the surface area of a cuboid/rectangular solid is 2(lw+wh+lh), how can we translate this into top/bottom/sides etc.?

Its super basic but I'm having trouble in translating top/bottom/sides wording into length, width and height. As the general formula for the surface area of a cuboid/rectangular solid is 2(lw+wh+lh), how can we translate this into top/bottom/sides etc.?

Thanks!

The length, width and height changes according to the orientation of the box. The height right now is 5 inches but if you turn it 90 degrees, it could be 25 inches. But the overall surface area and volume stays the same irrespective of what you consider as length, breadth and height. Hence the formulas are symmetrical: Surface Area = 2*(lb + bh + hl) Volume = lbh

If you interchange l and b, the formula stays the same. So it doesn't really matter what you take as length breadth and height.

In this question, they have specified the orientation of the box and hence the face which is lying at the bottom. That face is the one which has area of 25*10.

Hence the surface area of the rest can be calculated as 2*(25*10 + 10*5 + 5*25) - 25*10
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