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The perimeter of the square region S and the rectangular region R are equal. If the sides of R are in the ratio 2:3, what is the ratio of the area of the region R to the area of region S?
25:16
24:25
5:6
4:5
4:9
SOLVE!
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The perimeter of the square region S and the rectangular region R are equal. If the sides of R are in the ratio 2:3, what is the ratio of the area of the region R to the area of region S?
25:16
24:25
5:6
4:5
4:9
SOLVE!
Show more
4s equals 2l+2w.....l equals 2/3*w and the area of R is 2/3 *w^2
s equals l/2 + w/2, substituting we have 5/6 *w and s^2 equals 25/36 *w^2...so 2/3 * 36/25 equals 24/25....B
Can you break down these equations you used easier to read. I solved this by using a plug-in #s method, but tried with formulas. Having trouble following your formula after 4s = 2l + 2w.
The perimeter of the square region S and the rectangular region R are equal. If the sides of R are in the ratio 2:3, what is the ratio of the area of the region R to the area of region S?
25:16
24:25
5:6
4:5
4:9
SOLVE!
Show more
This problem was much easier to do once I got off my fat ass and did it on a piece of paper rather than in my head =)
anyway:
Lets say we have S as the side of square S.
4S=2l+2w
2l=3w --> l=1.5w
4S=2(1.5w)+2w --> 4S=5W --> S=5W/4
Now we want to know lw/s^2 --> s^2=25w^2/16
also plug in l on top
1.5w*w/25w^2/16---> 3/2*16/25 --> 48/50---> 24/25
B
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.