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Bunuel
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 03 Apr 2020, 04:25
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rectangle. If the other diagonal has the equation y = 3x + c, then c is

A. -5
B. -6
C. -7
D. -8
E. -9

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D
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 03 Apr 2020, 04:55
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Bunuel
The points (2, 5) and (6, 3) are two end points of a diagonal of a rectangle. If the other diagonal has the equation y = 3x + c, then c is

A. -5
B. -6
C. -7
D. -8
E. -9
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Since, diagonals of rectangle bisect each other, midpoint of (\(2, 5\)) & (\(6, 3\)) lies on the line \(y = 3x + c\)

Midpoint of (\(2, 5\)) & (\(6, 3\)) = (\(\frac{2 + 6}{2}, \frac{5 + 3}{2}\)) = (\(4, 4\))

--> \(4 = 3*4 + c\)
--> \(c = 4 - 12 = -8\)

Option D
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 03 Sep 2022, 09:20
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Bunuel
The points (2, 5) and (6, 3) are two end points of a diagonal of a rectangle. If the other diagonal has the equation y = 3x + c, then c is

A. -5
B. -6
C. -7
D. -8
E. -9

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if I know 2 end points of a Diagonal, I know the end points of the other diagonals since is a rectangle, (2,3) and (6,5) and with that I can calculate the slope of that line, but since we know that the slope is 3, (5-3)/(6-2) should be 3, which is not. What am I doing wrong?
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 03 Sep 2022, 15:35
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If the other diagonal has the equation y = 3x + c, shouldn't the two points of the opposite diagonal be on that line?

(6,5) y = 3x +c ---> 5= 3(6) +c ---> c = -13
(2,3) y = 3x +c ---> 3= 3(2) +c ---> c = -3

Thus, the points are not on the same line
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 04 Sep 2022, 00:10
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Given: The points (2, 5) and (6, 3) are two end points of a diagonal of a rectangle.

Asked: If the other diagonal has the equation y = 3x + c, then c is

Midpoint of (2,5) & (6,3) = (4,4)
Since diagonals of a rectangle bisect each other at midpoint of diagonals, the other diagonal should also pass through (4,4)

y = 3x + c
4 = 12 + c
c = 4- 12 = -8

IMO D
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 04 Sep 2022, 04:31
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Maria240895chile
Bunuel
The points (2, 5) and (6, 3) are two end points of a diagonal of a rectangle. If the other diagonal has the equation y = 3x + c, then c is

A. -5
B. -6
C. -7
D. -8
E. -9

Are You Up For the Challenge: 700 Level Questions

if I know 2 end points of a Diagonal, I know the end points of the other diagonals since is a rectangle, (2,3) and (6,5) and with that I can calculate the slope of that line, but since we know that the slope is 3, (5-3)/(6-2) should be 3, which is not. What am I doing wrong?
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The mistake is you’re assuming that the rectangle has horizontal and vertical sides ONLY. There are many rectangles possible for a fixed diagonal.
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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 06 Sep 2022, 10:48
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We should have the figure parallelogram instead. As a rectangle has all angles equal to 90 degree... It is not understood why the other two end points shouldn't be (2, 3) and (6, 5)....Please explain

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The points (2, 5) and (6, 3) are two end points of a diagonal of a rec 09 Jul 2025, 07:32
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