summerbummer
Bunuel
The points R, T, and U lie on a circle that has radius 4. If the length of arc RTU is \(\frac{4*\pi}{3}\), what is the length of line segment RU?
(A) 4/3
(B) 8/3
(C) 3
(D) 4
(E) 6
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Went through so many comments but still can't understand why RTU = 4 pi/3?
And how are the angles 60 degree?
I understand it's an isosceles triangle. Once we get RTU, we can find the angle then.
I'm stuck in this step!
Please help!
KarishmaB Bunuel BrentGMATPrepNowThe circle has radius 4 so the circumference of the circle is \(2*\pi*4 = 8*\pi\)
The question tells us that the length of arc RTU is \(\frac{4*\pi}{3}\).
\(Length Of Arc = Q/360 * Circumference\) (where Q is the central angle subtended by the arc)
\(\frac{4*\pi}{3} = Q/360 * 8*\pi\)
We get Q = 60 degrees
So the central angle RCU = 60 degrees. So sum of angles CRU and RUC = 180 - 60 = 120 degrees
Since RC = UC = Radius of circle,
This means angels CRU and RUC are equal. Since their sum is 120, each of these is 60 degrees angle too. So triangle RCU has all angles of 60 degrees and is an equilateral triangle. Then RU = 4.
Answer (D)