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02 Dec 2022, 09:59
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:30) correct
27%
(01:53)
wrong
based on 229
sessions
History
Date
Time
Result
Not Attempted Yet
The population of city X increased from 325,000 in 1980 to 350,000 in 1990, and it is projected that the population will increase by the same number from 1990 to 2000. Approximately what is the projected percent increase in population from 1990 to 2000 ?
(A) 7.1%
(B) 7.7%
(C) 8.3%
(D) 14.3%
(E) 15.3%
(A) 7.1%
(B) 7.7%
(C) 8.3%
(D) 14.3%
(E) 15.3%
28 Dec 2022, 08:45
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Bunuel
Population increase from 1980 to 1990 = 350,000 - 325,000 = 25,000
This means the population increase from 1990 to 2000 = 25,000
So, to find the projected percent increase from 1990 to 2000, we must convert \(\frac{25,000}{350,000}\) to a percent.
To do so, take: \(\frac{25,000}{350,000}\)
Divide numerator and denominator by 10,000 to get: \(\frac{2.5}{35}\)
STRATEGY: Rather than perform any long division here, we can use the property that k/100 = k%
So, we want to take \(\frac{2.5}{35}\) and multiply numerator and denominator by the same value so that the new (equivalent) fraction has 100 in the denominator.
To accomplish this, we will multiply numerator and denominator by a number a little bit less than 3.
When we do so we get: (some number a little bit less than 7.5)/100 which equals a little bit less than 7.5%, which means the correct answer must be A
08 Jan 2024, 08:19
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Bunuel
(350 - 325)/350*100 = 25/325*100 ~ 7.14%, Answer must be (A)
