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Senior Manager  Joined: 10 Jul 2013
Posts: 290
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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Question Stats: 59% (01:41) correct 41% (01:26) wrong based on 220 sessions

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The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment): What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0

Attachment:
File comment: Attachment function 23.png [ 14.46 KiB | Viewed 3414 times ]

Attachment: Untitled.png [ 10.85 KiB | Viewed 505 times ]

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Asif vai.....
Math Expert V
Joined: 02 Sep 2009
Posts: 58320
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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qlx wrote:
Asifpirlo wrote:
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment): What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0

Can some one please explain the table to me . As of now I am not able to comprehend the two tables of f(a,b ) and g(a, b).
in a 2*2 table , rows stand for something and column stand for something. In this sum what does row stand for and what does column stand for?

Thank you members. Yellow rows are the values of x, green columns are the values of y, and the red boxes are the outcomes of the functions f and g.

The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables:

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0. According to the second table we can have the following cases:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0;
a=1, b=0 --> f(a,b) + g(a,b) = 0 + 1 = 1;
a=0, b=1 --> f(a,b) + g(a,b) = 0 + 1 = 1.

Not sufficient.

(2) g(a,b) = 0. According to the first table we can have only the following case:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0.

Sufficient.

Hope it's clear.

Attachment: Untitled.png [ 12.48 KiB | Viewed 2753 times ]

Attachment: Untitled.png [ 6.48 KiB | Viewed 501 times ]

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Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
This could be $$a,b=0$$ and $$f(a,b) + g(a,b)=0$$; or could be $$a=0$$ and $$b=1$$ and $$f(a,b) + g(a,b)=1$$.
Not sufficient

(2) g(a,b)= 0
This works only for $$a,b=0$$ so $$f(a,b) + g(a,b)=0$$.
Sufficient
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Manager  Joined: 17 Mar 2014
Posts: 68
Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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1
Asifpirlo wrote:
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment) :

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0

Can some one please explain the table to me . As of now I am not able to comprehend the two tables of f(a,b ) and g(a, b).
in a 2*2 table , rows stand for something and column stand for something. In this sum what does row stand for and what does column stand for?

Thank you members.
Manager  Joined: 17 Mar 2014
Posts: 68
Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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Bunuel wrote:
qlx wrote:
Asifpirlo wrote:
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment) :

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0

Can some one please explain the table to me . As of now I am not able to comprehend the two tables of f(a,b ) and g(a, b).
in a 2*2 table , rows stand for something and column stand for something. In this sum what does row stand for and what does column stand for?

Thank you members.

Attachment:
Untitled.png
Yellow rows are the values of x, green columns are the values of y, and the red boxes are the outcomes of the functions f and g.

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0. According to the second table we can have the following cases:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0;
a=1, b=0 --> f(a,b) + g(a,b) = 0 + 1 = 1;
a=0, b=1 --> f(a,b) + g(a,b) = 0 + 1 = 1.

Not sufficient.

(2) g(a,b) = 0. According to the first table we can have only the following case:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0.

Sufficient.

Hope it's clear.

Great that clears it! I guess a real GMAT question could have mentioned horizontal row is x and vertical column is y.
Thank you.
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Joined: 17 Jul 2014
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Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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first time seeing a question with such notations. unless I see similar official question, I would rather disregard it...
Intern  B
Joined: 24 Jun 2017
Posts: 28
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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Bunuel wrote:
qlx wrote:
Asifpirlo wrote:
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment): What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0

Can some one please explain the table to me . As of now I am not able to comprehend the two tables of f(a,b ) and g(a, b).
in a 2*2 table , rows stand for something and column stand for something. In this sum what does row stand for and what does column stand for?

Thank you members. Yellow rows are the values of x, green columns are the values of y, and the red boxes are the outcomes of the functions f and g.

The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables:

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0. According to the second table we can have the following cases:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0;
a=1, b=0 --> f(a,b) + g(a,b) = 0 + 1 = 1;
a=0, b=1 --> f(a,b) + g(a,b) = 0 + 1 = 1.

Not sufficient.

(2) g(a,b) = 0. According to the first table we can have only the following case:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0.

Sufficient.

Hope it's clear.

hi bunuel , can't a=1 and b=1 also be a possible domain for f(a,b) as you have mentioned only 3 possible cases
Math Expert V
Joined: 02 Sep 2009
Posts: 58320
Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1  [#permalink]

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1
siddharth19 wrote:
Bunuel wrote:
Asifpirlo wrote:
The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables (Attachment): What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0
(2) g(a,b)= 0 Yellow rows are the values of x, green columns are the values of y, and the red boxes are the outcomes of the functions f and g.

The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1 and y = 0 or 1 and are defined by the following tables:

What is the value of f(a,b) + g(a,b) ?

(1) f(a,b) = 0. According to the second table we can have the following cases:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0;
a=1, b=0 --> f(a,b) + g(a,b) = 0 + 1 = 1;
a=0, b=1 --> f(a,b) + g(a,b) = 0 + 1 = 1.

Not sufficient.

(2) g(a,b) = 0. According to the first table we can have only the following case:
a=0, b=0 --> f(a,b) + g(a,b) = 0 + 0 = 0.

Sufficient.

Hope it's clear.

hi bunuel , can't a=1 and b=1 also be a possible domain for f(a,b) as you have mentioned only 3 possible cases

(1) says that f(a,b) = 0.

If, as you say, a = 1 and b = 1, then f(a,b) = f(1,1) = 1, not 0 (bottom right corner of table for f).
_________________ Re: The possible arguments of the functions f(x,y) and g(x,y) are x=0 or 1   [#permalink] 05 Mar 2019, 23:46
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