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Bunuel
The price of a certain computer is increased by 10%, and then the new price is increased by an additional 5%. The new price is what percent of the original price?

(A) 120%
(B) 119.5%
(C) 117%
(D) 115.5%
(E) 115%

Let the initial price of the computer be x
Price after first 10% increase = 1.1x
Price after second 5% increase = 1.1x * 1.05 = 1.155x

New price / original price = 1.155 = 115.5%

IMO D
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Let's say the computer costs 100$

100$+10% = 110$
110$+5% = 115,5$ (as 5% of 110 is 5,5)

115,5$/100$= 115,5%
Answer D)
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Let the original price be 100.

The price is increased by 10%: \(\frac{110}{100}\) * 100 = 110

The new price is increased by an additional 5%: \(\frac{105}{100}\) * 110 = 115.5

The new price is what percent of the original price: 115.5 = what percent * 100

=> 115.5 = \(\frac{what }{ 100}\) * 100

=> what = 115.5

Answer D
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Bunuel
The price of a certain computer is increased by 10%, and then the new price is increased by an additional 5%. The new price is what percent of the original price?

(A) 120%
(B) 119.5%
(C) 117%
(D) 115.5%
(E) 115%

Solution:

We can let the original price of the computer be $100. After two percentage increases in price, the new price is:

100 x 1.1 x 1.05 = $115.50

We see that 115.5 is 115.5% of 100.

Answer: D
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