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# The probability of pulling a black bal out of a glass jar is

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The probability of pulling a black bal out of a glass jar is [#permalink]

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10 Jul 2006, 16:58
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The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?

A. 1/(XY)
B. X/Y
C. Y/X
D. 1/(X+Y)
E. 1/(X-Y)

OPEN DISCUSSION OF THIS QUESTION IS HERE: the-probability-of-pulling-a-black-ball-out-of-a-glass-jar-106429.html
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Andre Crompton
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10 Jul 2006, 17:36
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andrecrompton wrote:
9. The probability of pulling a black bal out of a glass jar is 1/x. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/y. What is the probability of breaking the jar?

I thought it would be 1/(x-y) but that is wrong the answer is X/Y

Help me understand.

Let A - prb. of taking the ball out
B - prob. of breaking the jar

P(AB) = P(A) * P(B)
1/y = 1/x * P(B)
p(B) = x/y
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10 Jul 2006, 18:47
P(A and B) = P(A) * P(B)

1/y = 1/x * P(B)

P(B) = x/y
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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12 Sep 2014, 11:24
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Re: The probability of pulling a black bal out of a glass jar is [#permalink]

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13 Sep 2014, 06:04
andrecrompton wrote:
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?

A. 1/(XY)
B. X/Y
C. Y/X
D. 1/(X+Y)
E. 1/(X-Y)

Probability of A and B:
When two events are independent, the probability of both occurring is the product of the probabilities of the individual events: $$P(A \ and \ B) = P(A)*P(B)$$

P(break & black) = P(break) * P(black) --> 1/y=P(break)*1/x --> P(break)=x/y.

Answer: B.

OPEN DISCUSSION OF THIS QUESTION IS HERE: the-probability-of-pulling-a-black-ball-out-of-a-glass-jar-106429.html
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Re: The probability of pulling a black bal out of a glass jar is   [#permalink] 13 Sep 2014, 06:04
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# The probability of pulling a black bal out of a glass jar is

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