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Because her test turned out to be more difficult than she intended it

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Because her test turned out to be more difficult than she intended it  [#permalink]

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New post 01 May 2018, 05:16
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Question Stats:

61% (01:42) correct 39% (02:01) wrong based on 70 sessions

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Because her test turned out to be more difficult than she intended it to be, a teacher decided to adjust the grades by deducting only half the number of points a student missed. For example, if a student missed 10 points, she received a 95 instead of a 90. Before the grades were adjusted the class average was A. What was the average after the adjustment?


A. \(50 + \frac{A}{2}\)

B. \(\frac{1}{2}\) * \((100 - A)\)

C. \(100 -\) \(\frac{A}{2}\)

D. \(\frac{50 + A}{2}\)

E. \(A + 25\)

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Because her test turned out to be more difficult than she intended it  [#permalink]

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New post 01 May 2018, 06:04
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Bunuel wrote:
Because her test turned out to be more difficult than she intended it to be, a teacher decided to adjust the grades by deducting only half the number of points a student missed. For example, if a student missed 10 points, she received a 95 instead of a 90. Before the grades were adjusted the class average was A. What was the average after the adjustment?


A. \(50 + \frac{A}{2}\)

B. \(\frac{1}{2}\) * \((100 - A)\)

C. \(100 -\) \(\frac{A}{2}\)

D. \(\frac{50 + A}{2}\)

E. \(A + 25\)


The question tells you that 100 is the maximum score (from the example with 90 and 95). So you know that A=100-W where W is the number they got wrong.

Under the new system A' would be 100-\(\frac{W}{2}\). Right?

So Rearranging the first equation for W gives W=100-A and substituting gives:

\(A'=100-\frac{(100-A)}{2}=100-50+\frac{A}{2}=50+\frac{A}{2}\)

Hence A
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Re: Because her test turned out to be more difficult than she intended it  [#permalink]

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New post 02 May 2018, 10:23
Bunuel wrote:
Because her test turned out to be more difficult than she intended it to be, a teacher decided to adjust the grades by deducting only half the number of points a student missed. For example, if a student missed 10 points, she received a 95 instead of a 90. Before the grades were adjusted the class average was A. What was the average after the adjustment?


A. \(50 + \frac{A}{2}\)

B. \(\frac{1}{2}\) * \((100 - A)\)

C. \(100 -\) \(\frac{A}{2}\)

D. \(\frac{50 + A}{2}\)

E. \(A + 25\)


Since the average is A, we see that, on average, each student misses (100 - A) points. Since the teacher decided to deduct only half the number of points a student missed, on average, she deducted (100 - A)/2 points from each student. Therefore, the new average is:

100 - (100 - A)/2 = 100 - 100/2 + A/2 = 50 + A/2

Answer: A
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Re: Because her test turned out to be more difficult than she intended it  [#permalink]

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New post 02 Aug 2018, 00:32
Bunuel wrote:
Because her test turned out to be more difficult than she intended it to be, a teacher decided to adjust the grades by deducting only half the number of points a student missed. For example, if a student missed 10 points, she received a 95 instead of a 90. Before the grades were adjusted the class average was A. What was the average after the adjustment?


A. \(50 + \frac{A}{2}\)

B. \(\frac{1}{2}\) * \((100 - A)\)

C. \(100 -\) \(\frac{A}{2}\)

D. \(\frac{50 + A}{2}\)

E. \(A + 25\)


Question is simply asking which answer choice gives 95 marks when we use A equals 90.

Only answer choice A gives this .

50 + 90/2

= 95 (A)
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Re: Because her test turned out to be more difficult than she intended it &nbs [#permalink] 02 Aug 2018, 00:32
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