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Bunuel
Because her test turned out to be more difficult than she intended it to be, a teacher decided to adjust the grades by deducting only half the number of points a student missed. For example, if a student missed 10 points, she received a 95 instead of a 90. Before the grades were adjusted the class average was A. What was the average after the adjustment?


A. \(50 + \frac{A}{2}\)

B. \(\frac{1}{2}\) * \((100 - A)\)

C. \(100 -\) \(\frac{A}{2}\)

D. \(\frac{50 + A}{2}\)

E. \(A + 25\)

Since the average is A, we see that, on average, each student misses (100 - A) points. Since the teacher decided to deduct only half the number of points a student missed, on average, she deducted (100 - A)/2 points from each student. Therefore, the new average is:

100 - (100 - A)/2 = 100 - 100/2 + A/2 = 50 + A/2

Answer: A
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The total is 100 and the Average is 100.

Students miss (100-A)

Now as deduction is halved, new miss point is \(\frac{(100 - A)}{2}\)

New Average: 100 - \(\frac{100}{ 2} + \frac{A}{2}\)

=> 50 + \(\frac{A}{2}\)

Answer A
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