GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Feb 2019, 07:58

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
  • Free GMAT Algebra Webinar

     February 17, 2019

     February 17, 2019

     07:00 AM PST

     09:00 AM PST

    Attend this Free Algebra Webinar and learn how to master Inequalities and Absolute Value problems on GMAT.
  • Valentine's day SALE is on! 25% off.

     February 18, 2019

     February 18, 2019

     10:00 PM PST

     11:00 PM PST

    We don’t care what your relationship status this year - we love you just the way you are. AND we want you to crush the GMAT!

The sides of a quadrilateral taken in order are 16,16,14 and

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Senior Manager
Senior Manager
avatar
Joined: 30 Aug 2003
Posts: 315
Location: BACARDIVILLE
The sides of a quadrilateral taken in order are 16,16,14 and  [#permalink]

Show Tags

New post Updated on: 07 Mar 2004, 13:23
1
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

The sides of a quadrilateral taken in order are 16,16,14 and 10. The angle contained by the frist two sides is 60 degrees. What is teh area of the quadrilateral?

12(sqrt252)
104(sqrt3)
16(sqrt3)(4+sqrt15)
14(sqrt3)+5
what the...

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.


If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco


Originally posted by sunniboy007 on 07 Mar 2004, 12:25.
Last edited by sunniboy007 on 07 Mar 2004, 13:23, edited 1 time in total.
SVP
SVP
avatar
Joined: 30 Oct 2003
Posts: 1731
Location: NewJersey USA
  [#permalink]

Show Tags

New post 07 Mar 2004, 13:04
I dont know how to solve this without knowing the other angles.
Senior Manager
Senior Manager
avatar
Joined: 30 Aug 2003
Posts: 315
Location: BACARDIVILLE
  [#permalink]

Show Tags

New post 07 Mar 2004, 13:07
yes, it's a tough bugger!
I will give others a chance to answer it before I post the the official answer and reasoning.
_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

Senior Manager
Senior Manager
avatar
Joined: 05 Feb 2004
Posts: 281
Location: USA
  [#permalink]

Show Tags

New post 07 Mar 2004, 13:24
B it is.......... :-D !!
here's the soln:

1st 2 sides are 16 each and they form angle = 60 degrees
So If u draw a diagonal the triangle that contains diagonal and these 2 sides will be equilateral, with sides 16.
Therefore area of Triangle = (sqrt3/4)*16*16 =64*sqrt3
For the other triangles sides are=16,14,10
Hence its area = 40sqrt3
Area of quad = sum of 2 triangles = 104 sqrt3!! :punk
Senior Manager
Senior Manager
avatar
Joined: 30 Aug 2003
Posts: 315
Location: BACARDIVILLE
  [#permalink]

Show Tags

New post 07 Mar 2004, 13:30
:yikes :pray cbrf3
WOuld you like to take the GMAT for me? :lol:
_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

Director
Director
avatar
Joined: 03 Jul 2003
Posts: 636
  [#permalink]

Show Tags

New post 07 Mar 2004, 19:57
cbrf3 wrote:
For the other triangles sides are=16,14,10
Hence its area = 40sqrt3


What is the formula to find the area from the length of sides?
GMAT Club Legend
GMAT Club Legend
avatar
Joined: 15 Dec 2003
Posts: 4154
  [#permalink]

Show Tags

New post 07 Mar 2004, 20:47
kpadma wrote:
cbrf3 wrote:
For the other triangles sides are=16,14,10
Hence its area = 40sqrt3


What is the formula to find the area from the length of sides?

This requires 2 simple pythagorean formulas with 2 unknown. The workout is a bit longer than the simple answer posted by cbrf3 though
We can let base (b) = 16
The height of the second triangle will separate that triangle into 2 right triangles. Let X be the length of the shorter side of the base and (16-X) be the length of the longer side of the base.
h^2 = 10^2 - X^2
h^2 = 14^2 - (16-X)^2
100 - X^2 = 196 - (256-32X+X^2)
100 - X^2 = -60 + 32X - X^2
32X = 160 --> X = 5
Height would be equal to:
h^2 = 10^2 - 5^2
= 100 - 25 = 75
h = 5sqrt3
Area of second triangle is b*h/2 = 16*5sqrt3 / 2 = 40sqrt3
_________________

Best Regards,

Paul

Senior Manager
Senior Manager
User avatar
Joined: 06 Dec 2003
Posts: 340
Location: India
  [#permalink]

Show Tags

New post 07 Mar 2004, 21:32
Quote:
For the other triangles sides are=16,14,10
Hence its area = 40sqrt3



What is the formula to find the area from the length of sides?


Paul and KPADMA, the formula to find area of a triangle from measures of its sides is:

A = SQRT of (s*(s-a)*(s-b)*(s-c)) ; where s=1/2 (perimeter of triangle)

Hope, this will help

Dharmin
GMAT Club Legend
GMAT Club Legend
avatar
Joined: 15 Dec 2003
Posts: 4154
  [#permalink]

Show Tags

New post 07 Mar 2004, 21:45
Dharmin wrote:
Quote:
For the other triangles sides are=16,14,10
Hence its area = 40sqrt3



What is the formula to find the area from the length of sides?


Paul and KPADMA, the formula to find area of a triangle from measures of its sides is:

A = SQRT of (s*(s-a)*(s-b)*(s-c)) ; where s=1/2 (perimeter of triangle)

Hope, this will help

Dharmin

Awesome Dharmin. It sure simplifies things.

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.


If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________

Best Regards,

Paul

Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 9836
Premium Member
Re: The sides of a quadrilateral taken in order are 16,16,14 and  [#permalink]

Show Tags

New post 20 Jan 2019, 21:32
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

GMAT Club Bot
Re: The sides of a quadrilateral taken in order are 16,16,14 and   [#permalink] 20 Jan 2019, 21:32
Display posts from previous: Sort by

The sides of a quadrilateral taken in order are 16,16,14 and

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.