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11 Sep 2018, 02:49
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The size of a TV screen is given as the length of the screen's diagonal. If the screens were flat, then the diagonal of a square screen with an area of 98 square inches would be how many inches smaller than the diagonal of a square screen with an area of 162 square inches?
A. \(\sqrt{2}\)
B. 2
C. \(2\sqrt{2}\)
D. 4
E. 8
A. \(\sqrt{2}\)
B. 2
C. \(2\sqrt{2}\)
D. 4
E. 8
Updated on: 11 Sep 2018, 12:02
Originally posted by CounterSniper on 11 Sep 2018, 03:28.
Last edited by CounterSniper on 11 Sep 2018, 12:02, edited 2 times in total.
Last edited by CounterSniper on 11 Sep 2018, 12:02, edited 2 times in total.
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Bunuel
\(a^2\) = 98
a= 7\(\sqrt{2}\)
diagonal = 14
\(A^2\)=162
A = 9\(\sqrt{2}\)
diagonal = 18
difference in diagonal = 18-14=4
11 Sep 2018, 11:57
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Side of screen 1 = √98 = 7√2 ; diagonal = 7√2 * √2 = 14
side of screen 2 = √162 = 9√2; diagonal = 9√2 * √2 = 18
Difference = 4
side of screen 2 = √162 = 9√2; diagonal = 9√2 * √2 = 18
Difference = 4
