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Manager  Joined: 08 Oct 2010
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The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 77% (00:55) correct 23% (00:52) wrong based on 95 sessions

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The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

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Manager  Joined: 19 Aug 2010
Posts: 62
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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I first find the smallest possible number which is divisible by 4,6 and 7. With a prime factorization you can easily find that this number is 84.

Therefore, 86 (84+2) will be the smallest possible number which when divided by 4, 6 or 7 leaves a remainder of 2. Hence answer should be D.
Manager  Joined: 15 Apr 2010
Posts: 148
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:
a) 44
b) 62
c) 80
d) 86
e) none of these

A number will give a remainder only when it is greater than the multiple of the divisors.
In such problems, always start with the greatest divisor. In our case 7.

Test each number with 7. We are left with 44 & 86.
Now test 44 & 86 with 6. We are left with 44 & 86.
Now test 44 & 86 with 4. We are left with 86.

Alternatively after testing with 7 we can easily see that 44 is a multiple of 4. So we only test 86 with the remaining options.

Hope this helps.
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:
a) 44
b) 62
c) 80
d) 86
e) none of these

Pls, help with a solution method!?

Right, the solutions above are correct in their own way. But the way I think about this is the following :

The set of numbers that are divisible by numbers a,b,c are {LCM,LCMx2,LCMx3,...}
So what we need to know is the LCM of 4,6,7
LCM of these numbers is 84.

So the smallest number leaving remainder 2 will be 86

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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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1
1
feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

I have another vision of this problem:

In order to leave same remainder upon division by 4, 6 or 7 our number should be in the form:

$$N = LCM (4, 6, 7)*x + 2$$, where $$x >= 0$$

$$N = 84*x + 2$$

And we have AP starting from 2

$$2, 86, 170 ...$$

Smallest number in progression which leaves remainder 2 when divided by all of the 4, 6 and 7 is 2 not 86.

Bunuel please correct me if I'm wrong, may be I missed something.
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Location: Pune, India
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

Note that the smallest such number is 2.
When 2 is divided by 4, the quotient is 0 and remainder is 2.
Same logic for 6 and 7 too.

Out of the given options, the next smallest number will be LCM (4, 6, 7) + 2 = 86

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Karishma
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Senior Manager  B
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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VeritasPrepKarishma wrote:
feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

Note that the smallest such number is 2.
When 2 is divided by 4, the quotient is 0 and remainder is 2.
Same logic for 6 and 7 too.

Out of the given options, the next smallest number will be LCM (4, 6, 7) + 2 = 86

Dear Karishma

But why quotient should not be 0. The question asks about remainder not specifying the quotient. Why the whole number can not go into remainder without splitting into quotient and remainder? I can’t still get why 2 is not appropriate? Question asks about min number.

Senior Manager  B
Joined: 13 Oct 2016
Posts: 364
GPA: 3.98
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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Dear Karishma

Little more

The Number is in the form:

N=LCM(a,b,c)*n + 2

Why can't we take n=0?
Senior Manager  B
Joined: 13 Oct 2016
Posts: 364
GPA: 3.98
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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let-s-be-the-set-of-all-positive-integers-that-when-divided-by-8-hav-187551.html

In the question above in order to get oficial answer A we need to strat our progression from remainder itself (5) and our quotient is 0.

Can anybody explain why we can't use 2 as our answer here?

I think there should be phrazes like "different from remainder itself", "two digit number" or A<N<B in order to indicate some interval.

Many thanks and kudos for explanation from me.
Manager  B
Joined: 02 Nov 2013
Posts: 81
Location: India
Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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Another way of looking at the problem,
Going directly to the answer options, two answers can be omitted directly as they are divisible by 4 i.e. 44 and 80. We want the answer where after division from 4 remainder should be 2.
For remaining two should comply the equation 4x+2, 6x+2 and 7x+2.
Senior Manager  B
Joined: 13 Oct 2016
Posts: 364
GPA: 3.98
The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

Dear Prashantrchawla

Your approach is good and 86 definitely leaves remainder 2 when divided by 4, 6 and 7.

But, I have some doubts about this question. I think it’s trickier than it seems. The question does not ask which number from the list leaves remainder … or which smallest two digit number leaves remainder … or something of that sort. It simply and directly asks “what smallest number …” and smallest number is definitely 2 not 86.

But official answer says 86 so let it be. This will remain my personal dilemma .

Thanks for kudos by the way
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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1
vitaliyGMAT wrote:
VeritasPrepKarishma wrote:
feruz77 wrote:
The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44
b) 62
c) 80
d) 86
e) none of these

Note that the smallest such number is 2.
When 2 is divided by 4, the quotient is 0 and remainder is 2.
Same logic for 6 and 7 too.

Out of the given options, the next smallest number will be LCM (4, 6, 7) + 2 = 86

Dear Karishma

But why quotient should not be 0. The question asks about remainder not specifying the quotient. Why the whole number can not go into remainder without splitting into quotient and remainder? I can’t still get why 2 is not appropriate? Question asks about min number.

The answer should be 2. The quotient can be 0. I said in my post above that the smallest such number is 2. The options don't have 2 and hence we needed to ignore it. Else, the correct answer is 2 only.
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Karishma
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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Dear Karishma
Thanks a lot for confirmation
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde  [#permalink]

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IMO the correct answer should be E as the smallest number is 2!

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If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you. Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde   [#permalink] 26 Jan 2018, 09:34
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