Bunuel wrote:
The sum of 5 different positive 2-digit integers is 130. What is the highest possible value of the largest of these integers?
A. 88
B. 84
C. 78
D. 74
E. 68
Kudos for a correct solution.
Since the 5 numbers are all different, let's let A, B, C, D and E represent the numbers.
Furthermore, let's say A < B < C , D < E, which means E is the biggest value.
We're told that
A + B + C + D + E = 130In order to MAXIMIZE the value of E, we must MINIMIZE the other 4 values.
In other words, we want to MINIMIZE the value of A + B + C + D
Since the numbers must be 2-digit integers, the smallest values for A, B, C and D are 10, 11, 12 and 13 respectively.
So, plugging those values into our equation, we get:
10 + 11 + 12 + 13 + E = 130Simplify: 46 + E = 130
E = 84
Answer:
Cheers,
Brent
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