Bunuel wrote:

The sum of 5 different positive 2-digit integers is 130. What is the highest possible value of the largest of these integers?

A. 88

B. 84

C. 78

D. 74

E. 68

Kudos for a correct solution.

Since the 5 numbers are all different, let's let A, B, C, D and E represent the numbers.

Furthermore, let's say A < B < C , D < E, which means E is the biggest value.

We're told that

A + B + C + D + E = 130In order to MAXIMIZE the value of E, we must MINIMIZE the other 4 values.

In other words, we want to MINIMIZE the value of A + B + C + D

Since the numbers must be 2-digit integers, the smallest values for A, B, C and D are 10, 11, 12 and 13 respectively.

So, plugging those values into our equation, we get:

10 + 11 + 12 + 13 + E = 130Simplify: 46 + E = 130

E = 84

Answer:

Cheers,

Brent

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