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11 Aug 2019, 05:42
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Difficulty:
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Question Stats:
81% (00:56) correct
19%
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The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
11 Aug 2019, 06:10
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gvij2017
n+n+1+n+2+n+3+n+4= 35
n=5.
Two prime numbers out of 5.
C is correct.
n=5.
Two prime numbers out of 5.
C is correct.
n is not 5 but 7.
Let the numbers be, n, n+1, n-1, n+2 and n-2; adding them we get=> n*5=35, so n is 7,
Numbers: 7,8,6,9,5; Primes: 5 and 7.
