Join us for MBA Spotlight – The Top 20 MBA Fair      Schedule of Events | Register

 It is currently 05 Jun 2020, 12:24

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# The sum of five consecutive integers is 35. How many of the five conse

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 64314
The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 04:42
1
1
00:00

Difficulty:

25% (medium)

Question Stats:

78% (00:56) correct 22% (01:03) wrong based on 50 sessions

### HideShow timer Statistics

The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

_________________
Director
Joined: 08 Aug 2017
Posts: 732
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 04:47
n+n+1+n+2+n+3+n+4= 35
n=5.
Two prime numbers out of 5.
C is correct.
BSchool Moderator
Joined: 08 Dec 2013
Posts: 777
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB
GMAT 1: 630 Q47 V30
WE: Operations (Non-Profit and Government)
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 05:10
gvij2017 wrote:
n+n+1+n+2+n+3+n+4= 35
n=5.
Two prime numbers out of 5.
C is correct.

n is not 5 but 7.

Let the numbers be, n, n+1, n-1, n+2 and n-2; adding them we get=> n*5=35, so n is 7,

Numbers: 7,8,6,9,5; Primes: 5 and 7.
Intern
Status: Classified
Joined: 19 Jun 2019
Posts: 33
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 05:16
Bunuel wrote:
The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

Let the five consecutive integers be $$(n-2)$$, $$(n-1)$$, $$n$$, $$(n+1)$$, $$(n+2)$$.

Sum of the five consecutive integers is 35
$$\implies (n-2) + (n-1) + n + (n+1) + (n+2) = 35$$
$$\implies n = 7$$
$$\implies$$ The five consecutive numbers are $$5$$, $$6$$, $$7$$, $$8$$, $$9$$.

There are two prime numbers, $$5$$ and $$7$$, among them.
_________________
Best
CEO
Joined: 03 Jun 2019
Posts: 2948
Location: India
GMAT 1: 690 Q50 V34
WE: Engineering (Transportation)
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 06:38
LeoN88 wrote:
gvij2017 wrote:
n+n+1+n+2+n+3+n+4= 35
n=5.
Two prime numbers out of 5.
C is correct.

n is not 5 but 7.

Let the numbers be, n, n+1, n-1, n+2 and n-2; adding them we get=> n*5=35, so n is 7,

Numbers: 7,8,6,9,5; Primes: 5 and 7.

Both approaches are correct and yield the same result

First Approach: -
If we assume numbers as n, n+1, n+2, n+3 and n+4 then
n+n+1+n+2+n+3+n+4 = 5n+10 = 35
n=25/5 = 5

Numbers are 5,6,7,8 & 9
5 & 7 are prime

IMO C

Second Approach: -
If we assume numbers as n, n+1, n+2, n-1 and n-2 then
n+n+1+n+2+n-1+n-2 = 5n = 35
n=35/5 = 7

Numbers are 5,6,7,8 & 9
5 & 7 are prime

IMO C

But the end result of both approaches is the same.

It is better to assume 5 consecutive integers as n-2 ,n-1, n, n+1, n+2 since it eases the calculations in most cases.
_________________
Kinshook Chaturvedi
Email: kinshook.chaturvedi@gmail.com
GMAT Club Legend
Joined: 18 Aug 2017
Posts: 6320
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 09:39
Bunuel wrote:
The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

given
5x+10=35
x=5
so series ; 5,6,7,8,9
2 prime
IMO C
VP
Joined: 07 Dec 2014
Posts: 1253
The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 11:16
Bunuel wrote:
The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

mean=35/5=7
sequence=5,6,7,8,9
2
C
VP
Joined: 18 Dec 2017
Posts: 1381
Location: United States (KS)
GMAT 1: 600 Q46 V27
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

11 Aug 2019, 11:39
Bunuel wrote:
The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

5+6+7+8+9 is 35. 2 numbers are prime in this.
IMO C.
_________________
The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long

Why You Don’t Deserve A 700 On Your GMAT

Learn from the Legend himself: All GMAT Ninja LIVE YouTube videos by topic
You are missing on great learning if you don't know what this is: Project SC Butler
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 10669
Location: United States (CA)
Re: The sum of five consecutive integers is 35. How many of the five conse  [#permalink]

### Show Tags

14 Aug 2019, 16:46
1
Bunuel wrote:
The sum of five consecutive integers is 35. How many of the five consecutive integers are prime numbers?

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

The sum of 5, 6, 7, 8, and 9 is 35. Of these five numbers, 5 and 7 are prime numbers.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
202 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Re: The sum of five consecutive integers is 35. How many of the five conse   [#permalink] 14 Aug 2019, 16:46