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The table above shows the distribution of test scores for a [#permalink]
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07 Apr 2012, 15:54
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SCORE INTERVALNUMBER OF SCORES 5059 2 606910 707916 808927 909918 The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 73 scores? A. 6069 B. 7079 C. 8089 D. 9099 E. It cannot be determined from the information given.
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Last edited by Bunuel on 12 Jun 2016, 06:43, edited 3 times in total.
Edited the question and added the OA



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Since there are 73 scores so the median will be the 37th score from the starting. Which will lie in the 8089 interval sot eh answer will be C Hope it helps!
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Re: The table above shows the distribution of test scores for a [#permalink]
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09 Nov 2012, 07:47
we are asked to find the median of the 73 scores, which is the 37th term. Now if we arrange the number of scores( not score intervals ) in ascending order as shown below which is what we do when we want to calculate the median of a number of terms:the Median term 37th falls in the 9099 interval. Confused as to , why we shouldn't arrange the frequency ( no. of scores in a particular interval ) in ascending order when calculating the Median. 5059 2 606910 707916 909918 808927
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23 May 2014, 14:04
Even I have the same question. I too followed this method and got the interval 9099 Any help here? stne wrote: we are asked to find the median of the 73 scores, which is the 37th term.
Now if we arrange the number of scores( not score intervals ) in ascending order as shown below which is what we do when we want to calculate the median of a number of terms:the Median term 37th falls in the 9099 interval.
Confused as to , why we shouldn't arrange the frequency ( no. of scores in a particular interval ) in ascending order when calculating the Median.
5059 2 606910 707916 909918 808927
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Re: The table above shows the distribution of test scores for a [#permalink]
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24 May 2014, 00:26
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stne wrote: we are asked to find the median of the 73 scores, which is the 37th term.
Now if we arrange the number of scores( not score intervals ) in ascending order as shown below which is what we do when we want to calculate the median of a number of terms:the Median term 37th falls in the 9099 interval.
Confused as to , why we shouldn't arrange the frequency ( no. of scores in a particular interval ) in ascending order when calculating the Median.
5059 2 606910 707916 909918 808927 Hi Stne, To find median of testscores,we have to arrange them in an order (ascending or descending) and find the middle term.Now,the middle term is 37 th term in the order. For the score distribution ,one can add one more column Cumulative frequency SCORE INTERVALNUMBER OF SCORES  Cumulative Frequency5059 2 2 606910 12 707916 288089 2755 909918 73We can see arranging the scores in ascending, shows first 28 test scores are below 80. Next 27 scores , i.e. 29th,30th,...., 37th,......,55th score appear in SCORE INTERVAL 8089. So median is in interval 8089. Hope it helps. Please press kudos if it helped.Kudos is the best form of appreciationKindly check the post with the poll and revert with your replies 10straightlinesnotwoofwhichareparallelandnothree171525.html



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Re: The table above shows the distribution of test scores for a [#permalink]
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24 Sep 2014, 23:18
gmatacequants wrote: stne wrote: we are asked to find the median of the 73 scores, which is the 37th term.
Now if we arrange the number of scores( not score intervals ) in ascending order as shown below which is what we do when we want to calculate the median of a number of terms:the Median term 37th falls in the 9099 interval.
Confused as to , why we shouldn't arrange the frequency ( no. of scores in a particular interval ) in ascending order when calculating the Median.
5059 2 606910 707916 909918 808927 Hi Stne, To find median of testscores,we have to arrange them in an order (ascending or descending) and find the middle term.Now,the middle term is 37 th term in the order. For the score distribution ,one can add one more column Cumulative frequency SCORE INTERVALNUMBER OF SCORES  Cumulative Frequency5059 2 2 606910 12 707916 288089 2755 909918 73We can see arranging the scores in ascending, shows first 28 test scores are below 80. Next 27 scores , i.e. 29th,30th,...., 37th,......,55th score appear in SCORE INTERVAL 8089. So median is in interval 8089. Hope it helps. Please press kudos if it helped.Kudos is the best form of appreciationKindly check the post with the poll and revert with your replies 10straightlinesnotwoofwhichareparallelandnothree171525.htmlJust a small thing to add.... If the sequence is placed in the reverse order (starting 9099 to end at 5059), the answer remains the same
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Re: The table above shows the distribution of test scores for a [#permalink]
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22 Oct 2014, 12:31
Bunuel wrote: rpamecha wrote: SCORE INTERVALNUMBER OF SCORES
5059 2 606910 707916 808927 909918
The table shown above has distribution of test scores. Which score interval contains the median of the 73 scores?
A. 6069 B. 7079 C. 8089 D. 9099 E. Cannot be determined.
Please explain your answer. Median of 73 data points is the middle term  37rd score. First 3 score ranges cover total of 28 scores (2+10+16), 37rd will be in fourth range (it covers scores from 80 to 89). Answer: C. Dear Bunnel, As I know, the arrangement either in ascending or in descending order is a must in case of finding median. So, it would be 2+10+16+18+27. By adding 2+10+16 we get 28. Then, we need to add 18 and we get 46. So, 37 comes within 46 and the range should be 9099 as it is the range for 18. Kindly tell me where I missed.



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22 Oct 2014, 13:09
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deya wrote: Bunuel wrote: rpamecha wrote: SCORE INTERVALNUMBER OF SCORES
5059 2 606910 707916 808927 909918
The table shown above has distribution of test scores. Which score interval contains the median of the 73 scores?
A. 6069 B. 7079 C. 8089 D. 9099 E. Cannot be determined.
Please explain your answer. Median of 73 data points is the middle term  37rd score. First 3 score ranges cover total of 28 scores (2+10+16), 37rd will be in fourth range (it covers scores from 80 to 89). Answer: C. Dear Bunnel, As I know, the arrangement either in ascending or in descending order is a must in case of finding median. So, it would be 2+10+16+18+27. By adding 2+10+16 we get 28. Then, we need to add 18 and we get 46. So, 37 comes within 46 and the range should be 9099 as it is the range for 18. Kindly tell me where I missed. I think you misinterpreted the question. We have that there are: 2 scores from 5059, say both are 55; 10 scores from 6069, say all are 65; 16 scores from 7079, say all are 75; 27 scores from 8089, say all are 85; 18 scores from 9099, say all are 95. 55, 55, 65, 65, 65, 65, 65, 65, 65, 65, 65, 65, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 75, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 85, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95, 95. Similar question to practice: thetableaboveshowsthedistributionoftestscoresfora93978.htmlHope it helps.
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Re: The table above shows the distribution of test scores for a [#permalink]
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21 Feb 2015, 20:20
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Median is the "middle value" when all the data are arranged in ascending/descending order. For example, if the data is:
3,4,7,9, 87 > Median is 7 (middle value).
Notice that there were 5 data points above, and the middle value is the 3rd value.
Here, there are 73 data points and so, the middle value will be 37th value. So, we just have to find out that 37th value will lie in which score interval.
2 values are lesser than 59 12 (2+10) values are lesser than 69 28 (2+10+16) values are lesser than 79 55 (2+10+16+27) values are lesser than 89
So, if 28 values are lesser than 79 and 55 values are lesser than 89
clearly 37th value will lie in the 8089 bracket.



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04 Mar 2015, 20:32
Tricky question !!
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12 Aug 2015, 04:51
Can someone please explain me in prcise details what is the meaning of the the question? I have a hard time understanding the actual question like what do they mean by distribution by interval how is range coming here etc? Thanks a million.



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12 Aug 2015, 05:03
Dreams25 wrote: Can someone please explain me in prcise details what is the meaning of the the question? I have a hard time understanding the actual question like what do they mean by distribution by interval how is range coming here etc? Thanks a million. Bunuel has aptly provided the answer above. But let me try it once more. The given intervals are 5059 2 606910 707916 808927 909918 You are asked to find the median value and median of a set is the middle most value (for odd number of elements) in a set in which all elements are ordered either in increasing or in decreasing order. For this question, we will focus on the increasing nature of the elements. As the total number of elements = 73, an odd number, the median will be the 37th term. So you need to find in what interval will be 37th lie in From the data set provided, you have 2 people in 5059 range, 10 people in 6069 etc. Thus if you have to write the set , you will get the following method 5059, 5059, 6069, 6069 (repeat 8 more times), 7079 (16 times), 8089 (27 times) and 9099 (18 times). Thus, the 37th term will be after 2 for 5059, 10 of 6069 , 16 of 7079 and 9 of 8089 for a total of 2+10+16+9 = 37. Thus the median value will lie in the interval 8089. C is the correct answer.
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12 Aug 2015, 05:08
What does it mean 2 people in 5059 range, 10 people in 6069



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26 Jun 2016, 22:28
rpamecha wrote: SCORE INTERVALNUMBER OF SCORES
5059 2 606910 707916 808927 909918
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 73 scores?
A. 6069 B. 7079 C. 8089 D. 9099 E. It cannot be determined from the information given. Median of a set with odd number of elements = the middle element of the set if arranged in ascending/descending order. Median of a set with even number of elements = average of middle two numbers if arranged in ascending/descending order. In the given case, total elements = 2 + 10 + 16 + 27 + 18 = 73 = 36 + 1 + 36 Hence the median will be the 37th term. The 37th term will lie in the range 80  89 Correct Option: C
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20 Jul 2016, 03:38
In this question, what is the value of data? Is it counted as 1 or 9?
5059 is counted as 1 or 9? Even though the value of mean is not asked I wanted to calculate it but I don't know what sum to take.



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20 Jul 2016, 03:41
bimalr9 wrote: In this question, what is the value of data? Is it counted as 1 or 9?
5059 is counted as 1 or 9? Even though the value of mean is not asked I wanted to calculate it but I don't know what sum to take. You can't calculate the mean of the data as mean requires data points themselves and NOT the ranges or intervals. Posted from my mobile device
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20 Jul 2016, 21:29
bimalr9 wrote: In this question, what is the value of data? Is it counted as 1 or 9?
5059 is counted as 1 or 9? Even though the value of mean is not asked I wanted to calculate it but I don't know what sum to take. We are given the range of the values here. The actual values can be "51 and 52" or "58 and 59" So, we cannot calculate the mean in this case.
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10 Dec 2016, 22:44
Below solution is more clear. Median of 73 scores must be the 37th score when all the scores are arranged in increasing or decreasing order. In the score interval 5079 there are (2 + 10 + 16) = 28 scores. Hence the 37th score is not in this interval. But in the score interval 5089 there are (2 + 10 + 16 + 27) = 55 scores. Hence the 37th score is in the score interval 8089. The correct answer is C.
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