A factory has three machines: A, B, and C.
- Machine A alone can complete a task in 6 hours.
- Machine B alone can complete the same task in 4 hours.
- Machine C alone can complete it in 3 hours.
All three machines start working together, but after 1 hour, Machine C breaks down and stops. Machine A and B continue working for another 2 hours, after which Machine A also stops. How much longer will it take for Machine B to finish the remaining work?
Solution Approach:
Step 1: Work Done Per Hour
- Machine A’s rate: 1/6 of the task per hour
- Machine B’s rate: 1/4 of the task per hour
- Machine C’s rate: 1/3 of the task per hour
- Together, their combined rate:
1/6 + 1/4 + 1/3
Finding a common denominator (12):
2/12 + 3/12 + 4/12 = 9/12 = 3/4
So, when all three machines work together, they complete 3/4 of the task per hour
Step 2: Work Done in 1 Hour (Before C Breaks Down)
1 × 3/4 = 3/4
So, 3/4 of the task is completed, and 1/4 of the task remains
Step 3: Work Done in the Next 2 Hours (Only A and B Working)
- A and B together work at a rate of:
1/6 + 1/4 = 2/12 + 3/12 = 5/12
- In 2 hours, they complete:
2 × 5/12 = 10/12 = 5/6
Step 4: Remaining Work
- The total task was 1, and so far, we've completed:
3/4 + 5/6
Converting to a common denominator (12):
9/12 + 10/12 = 19/12
But since the task is only 1 whole unit, we see they’ve overcompleted the task
Final Answer:
After 1 hour of all machines working together and 2 hours of A & B working together, the task is already completed
Takeaway:
This problem highlights the importance of checking your work carefully before assuming a final step is needed. The GMAT loves to test whether you’re blindly following a formula or actually thinking through the problem logically.
Would you have caught this before continuing? Let me know in the comments!