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The Ultimate Q51 Guide [Expert Level]

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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GMAT 1: 800 Q59 V59
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Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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29 Nov 2016, 04:28
Also, integer questions constantly appear recently.

If m and n are positive integers, is $$n^m-n$$ divisible by 6?

1) m=3
2) n=2

==> In the original condition, there are 2 variables (m,n), and in order to match the number of variables to the number of equations, there must be 2 equations. Therefore, C is most likely to be the answer. By solving con 1) and con 2), from $$2^3-2=6$$, you get yes, and hence it is sufficient. The answer is C. However, this question is an integer question, one of the key questions, so you need to apply CMT 4. For con 1), from $$n^3-n$$=(n-1)n(n+1), it is the multiple of the three consecutive integers, which always becomes the multiple of 6, hence yes, it is sufficient. For con 2), from n=2 and m=3 yes, m=2 no, and hence it is not sufficient. Therefore, the answer is A.

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 02 Dec 2016, 02:01 |a-b|=b-a? 1) a<b 2) ab<0 and $$a^2b$$=1 ==> If you modify the original condition and question, to get |A|=-A, you need to get A≤0?, so it becomes |a-b|=b-a=-(a-b)?, a-b<0?, a<b?. Thus, for con 1), it is always yes, hence sufficient, and for con 2), if you apply CMT 4 (B), it also becomes a<b, hence yes, it is sufficient. Therefore, the answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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05 Dec 2016, 19:14
) If x is a positive integer greater than 1, is 1/x a terminating decimal?

1) x has 3 as a factor
2) x is a factor of 81

==> If you modify the original condition and the question, to get 1/x as the terminating decimal, only 2 or 5 can be the prime factors of denominator x. However, for con 2), in order for x to become factors of 81=34, only 3 can be the prime factor of x, hence no, it is sufficient. Therefore, the answer is B.
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 08 Dec 2016, 18:31 x=? 1) $$1.1x=-1.2x$$ 2) $$1.1x^2=-1.2x^2$$ ==> In the original condition, there is 1 variable (x), and in order to match the number of variables to the number of equations, there must be 1 equation as well. Therefore, D is most likely to be the answer. For con 1), you get from $$2.3x=0$$ to x=0, hence it is unique and sufficient, and For con 2), you get from $$2.3x^2$$=0 to x=0, hence it is also unique and sufficient. Therefore, the answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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12 Dec 2016, 02:16
As always, more advanced questions related to mistake type 3 and 4 are being released. Look at the below. This question, a 5051-level question, was released recently, and it also falls into the mistake type 4(A). You must strengthen your skills in these type of questions. You need to know the relationship between variable approach and mistake types.

If the average (arithmetic mean) of 3 integers a, b, and c is 5, what is the value of a?

1) b=7
2) b=1-c

==> If you modify the original condition and the question and look at the question again, from a+b+c=15, you get a=15-(b+c), so you only need to know b+c. From con 2), you get b+c=1, so from a=15-(b+c)=15-1=14, it is unique and sufficient.

Therefore, the answer is B. This question is related to mistake type 4(A).

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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 14 Dec 2016, 19:57 The integer question below is also a 5051-level question. If x and y are prime numbers, what is the smallest prime factor of $$xy^3$$ ? 1) x=even 2) x+y=odd ==> In the original condition, there are only 2 variables (x, y), hence C is most likely to be the answer. For con 1), if x=even, an even number that is also a prime number is only “2”, so the smallest prime factor of $$xy^3$$ becomes 2, and hence it is sufficient. For con 2), in order to get x+y=odd, since it is even+odd=odd, x or y always becomes “2”, so the smallest prime factor of $$xy^3$$ becomes “2”, and hence it is also sufficient. This question is also related to mistake type 4(B), where con 1) is easy and con 2) is difficult. This type of question is a 5051-level question. The answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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18 Dec 2016, 23:49
You must be careful with inequality questions as below.

If $$a^3b^4c^5<0$$, is $$ab^2<0$$?

1) a<0
2) c>0

==> If you modify the original condition and the question and look at the question again, from If $$a^3b^4c^5<0$$, there are only odd variables, so you get If ac<0. Then, the que is $$ab^2<0$$? becomes a<0?, and hence con 1) is yes and sufficient. Also, from ac<0, you get c>0?, and hence con 2) is yes and sufficient.

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 21 Dec 2016, 19:09 If ab=c, b=? 1) c≠0 2) |a-c|≤0 ==> In the original condition, there are 3 variables (a, b, c) and 1 equation (ab=c). In order to match the number of variables to the number of equations, there must be 2 equations, and therefore C is most likely to be the answer. By solving con 1) and con 2), from con 2), you get a=c, and if you substitute this into ab=x, you get ab=a. In order to divide a from both sides, it needs to be a≠0. From con 1), it is c=a≠0, and if you divide both sides by a, you get b=1, hence it is unique and sufficient. Therefore, the answer is C. Answer: C _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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26 Dec 2016, 18:11
If m and n are positive integers, when $$3^4^n$$+m is divided by 5, what is the remainder?

1) n=1
2) m=4

==> If you modify the original condition and the question, you only need to know “m” from $$3^4^n+m= (34)^n+m=(81)n+m=(~1)+m$$, so the answer is B.
This type of question is a 5051-level question related to mistake type 4(A).

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 31 Dec 2016, 01:58 1) As always, more developed questions combined with CMT 3 and 4 are being released. Look at the question below. This question, a 5051-level question including CMT 4(A), was released recently. To strengthen your skills for this type of questions, you need to know the relationship between variable approach and CMT. If a and b are integers, is ab an odd? 1) a=0 2) b=1-a ==> In the original condition, there are 2 variables (a, b), and therefore C is most likely to be the answer. By solving con 1) and con 2), from a=0 and b=1, you get ab0*1=0=even, hence no, it is sufficient. Therefore, C is the answer. However, this is an integer question, one of the key questions. Thus, if you apply CMT 4 (A, B), if 1) a=0, you get ab=0 and it is always even, hence no, it is sufficient. Also, for con 2), from a+b=1=odd, and (a, b)=(odd, even), (even, odd), you get ab=even, hence yes, it is sufficient. Therefore, the answer is D. This question is related to CMT 4(B). In other words, con 1) is easy and con 2) is difficult, so you apply CMT 4(B) (If you get A and B easily, consider B). Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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02 Jan 2017, 19:08
The question below is also a 5051-level question.

If x, y and z are different integers, what is the value of y?

1) The average (arithmetic mean) of x, y and z is 2
2) x<y<z

==> In the original condition, there are 3 variables (x, y, z), and in order to match the number of variables to the number of equations, there must be 3 equations, and therefore E is most likely to be the answer. By solving con 1) & con 2), you get (x+y+z)/3=2. Since it is x<y<z, you always get median=average=y=2. Hence it is unique and sufficient.

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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 03 Jan 2017, 18:38 If r and s are positive integers, is r+s an odd number? 1) r and s are consecutive 2) r=s+1 ==> In the original condition, there are 2 variables (r, s), and therefore C is most likely to be the answer. By solving con 1) & con 2), you get con 1) = con 2), so it becomes r+s=s+1+s=2s+1=odd, and hence it is yes and sufficient. Therefore, the answer is D. This is a 5051-level question related to mistake type 4(B). Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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05 Jan 2017, 05:55
Is 1/a>1/b?

1) a<b
2) a<b<0

==> If you modify the original condition and the question and check the question again, you get a<b<0--> 1/a>1/b. In other words, it does not become a<b --> 1/a>1/b.

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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 08 Jan 2017, 18:14 If ab=0, is |a-b|>0? 1) a=0 2) b<0 ==> If you modify the original condition and the question, you get is a≠b? Also, there are 2 variables (a, b) and 1 equation (ab=0), in order to match the number of variables to the number of equations, there must be 1 equation as well, and therefore D is most likely to be the answer. For con 1), you get a=b=0 no a=0 and b=3, hence yes, it is not sufficient. For con 2), you get b<0 and a=0, hence yes, it is sufficient. Therefore, the answer is B. Answer: B _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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11 Jan 2017, 17:58
What is the median of the 5 consecutive integers?

1) The average (arithmetic mean) of the 5 consecutive numbers is 5
2) The average (arithmetic mean) of the 5 consecutive numbers is an odd number

==> In the original condition, there is 1 variable (and, n+1, n+2, n+3, n+4), and in order to match the number of variables to the number of equations, there must be 1 equation as well. Therefore, D is most likely to be the answer.
For con 1), in case of consecutive numbers, you get median=mean, and thus median=5 and it is sufficient.
For con 2), median=1,3,5,.. and hence it is not unique and not sufficient. Therefore, it is a question where A becomes the answer, but you must be aware of CMT 3. Con 2) and con 1) must be independent from each other, and you can’t assume that they are the same after solving con 1).

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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 5068 GMAT 1: 800 Q59 V59 GPA: 3.82 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 12 Jan 2017, 18:57 Is (a-1)(b+1)=0? 1) $$(a-1)^2=0$$ 2) $$|a-1|+(b+1)^2=0$$ ==> In the original condition, there are 2 variables (a, b), so there must be 2 more equations. Therefore, C is most likely the answer. By solving con 1) and con 2), you get con 1) = con 2), and a=1 and b=-1, hence it is always yes. The answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 3 month Online Course"
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Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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13 Jan 2017, 04:15
Hello Math revolution

You mentioned in your post that integer questions are very important and if someone gets all integer questions correct, then he can score a good 49 or so.

What is the reason behind this ? Are the first 20 questions mainly integer questions?

Thanks
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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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15 Jan 2017, 18:47
$$2^a2^b<4$$?

1) a+b<1.
2) a+b>0.

==> If you modify the original condition and the question, from $$2^a^+^b<4=2^2$$, you get a+b<2? Then, for con 1), the range of the question includes the range of the condition, and therefore it is sufficient.
For con 2), you get a+b=1 yes, but a+b=3 no, and therefore it is not sufficient.
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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Senior Manager Joined: 24 Jun 2016 Posts: 255 Location: Viet Nam Schools: Booth '19 GMAT 1: 770 Q60 V60 GPA: 4 Re: The Ultimate Q51 Guide [Expert Level] [#permalink] Show Tags 15 Jan 2017, 21:14 MathRevolution wrote: The question below is also a 5051-level question. If x, y and z are different integers, what is the value of y? 1) The average (arithmetic mean) of x, y and z is 2 2) x<y<z ==> In the original condition, there are 3 variables (x, y, z), and in order to match the number of variables to the number of equations, there must be 3 equations, and therefore E is most likely to be the answer. By solving con 1) & con 2), you get (x+y+z)/3=2. Since it is x<y<z, you always get median=average=y=2. Hence it is unique and sufficient. The answer is C. Answer: C Your solution is wrong. You can let x = -2, y = 0, z = 8 and still meet all of the conditions. You are confounding the mean with the median. E is the correct answer choice. _________________ Offering top quality online and offline GMAT tutoring in SoCal and worldwide.$60/hour as of November 2017.

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 5068
GMAT 1: 800 Q59 V59
GPA: 3.82
Re: The Ultimate Q51 Guide [Expert Level] [#permalink]

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16 Jan 2017, 18:55
Is n an even?
1) 3n=even
2) 5n=even

==> In the original condition, there is 1 variable (n), and therefore D is most likely to be the answer. For con 1) n=2 yes and n=2/3 no, so it is not sufficient.
For con 2), n=2 yes and n=2/5 no, so it is not sufficient. By solving con 1) and con 2), you always get n=even, and hence it is sufficient.

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"Only $79 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Re: The Ultimate Q51 Guide [Expert Level] [#permalink] 16 Jan 2017, 18:55 Go to page Previous 1 ... 6 7 8 9 10 11 12 ... 23 Next [ 459 posts ] Display posts from previous: Sort by The Ultimate Q51 Guide [Expert Level]  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Moderator: HKD1710  HOT DEALS FOR MARCH Math Revolution -$79/3 mo Special sale until March 31 Economist GMAT - Free Free 1-week trial + Free Test examPAL - Free A full GMAT video course, 100% free Kaplan Courses - Save $475$225 Discount + $250 Bonus Target Test Prep - Save$800 $50 Discount +$750 Bonus [GMAT ClubTests and Premium MBA Bundle] EMPOWERgmat - $99/mo GMAT Club tests included 2nd month GMAT Club Tests - Free Included with every course purchaseof$149 or more - Full List is here

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