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# The value of a silver coin varies directly as the square of its diamet

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Math Expert
Joined: 02 Sep 2009
Posts: 62353
The value of a silver coin varies directly as the square of its diamet  [#permalink]

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28 Dec 2019, 00:31
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Difficulty:

55% (hard)

Question Stats:

55% (02:29) correct 45% (01:49) wrong based on 20 sessions

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The value of a silver coin varies directly as the square of its diameter, when thickness is constant and varies directly as its thickness when diameter remains constant. Two silver coins have the diameters in the ratio 4 : 3. Find the ratio of the thickness if the value of the first coin is four times the value of the second coin.

A. 3 : 4
B. 4 : 3
C. 16 : 3
D. 9 : 4
E. 1 : 3

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Re: The value of a silver coin varies directly as the square of its diamet  [#permalink]

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28 Dec 2019, 14:54
$$V= k*d^2*t$$

$$\frac{V_1}{V_2}= \frac{k*(D_1)^2*t_1}{ k*(D_2)^2*t_2}$$

$$4= \frac{16*t_1}{9*t_2}$$

$$\frac{t_1}{t_2}= \frac{9}{4}$$

Bunuel wrote:
The value of a silver coin varies directly as the square of its diameter, when thickness is constant and varies directly as its thickness when diameter remains constant. Two silver coins have the diameters in the ratio 4 : 3. Find the ratio of the thickness if the value of the first coin is four times the value of the second coin.

A. 3 : 4
B. 4 : 3
C. 16 : 3
D. 9 : 4
E. 1 : 3
Re: The value of a silver coin varies directly as the square of its diamet   [#permalink] 28 Dec 2019, 14:54
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