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Math Expert V
Joined: 02 Sep 2009
Posts: 62353
The value of a silver coin varies directly as the square of its diamet  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 55% (02:29) correct 45% (01:49) wrong based on 20 sessions

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The value of a silver coin varies directly as the square of its diameter, when thickness is constant and varies directly as its thickness when diameter remains constant. Two silver coins have the diameters in the ratio 4 : 3. Find the ratio of the thickness if the value of the first coin is four times the value of the second coin.

A. 3 : 4
B. 4 : 3
C. 16 : 3
D. 9 : 4
E. 1 : 3

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DS Forum Moderator V
Joined: 19 Oct 2018
Posts: 1419
Location: India
Re: The value of a silver coin varies directly as the square of its diamet  [#permalink]

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$$V= k*d^2*t$$

$$\frac{V_1}{V_2}= \frac{k*(D_1)^2*t_1}{ k*(D_2)^2*t_2}$$

$$4= \frac{16*t_1}{9*t_2}$$

$$\frac{t_1}{t_2}= \frac{9}{4}$$

Bunuel wrote:
The value of a silver coin varies directly as the square of its diameter, when thickness is constant and varies directly as its thickness when diameter remains constant. Two silver coins have the diameters in the ratio 4 : 3. Find the ratio of the thickness if the value of the first coin is four times the value of the second coin.

A. 3 : 4
B. 4 : 3
C. 16 : 3
D. 9 : 4
E. 1 : 3 Re: The value of a silver coin varies directly as the square of its diamet   [#permalink] 28 Dec 2019, 14:54
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# The value of a silver coin varies directly as the square of its diamet  