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The vertices of rectangle ABCD are (12,5), (-12,5), (-12,-5)

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Manager
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The vertices of rectangle ABCD are (12,5), (-12,5), (-12,-5) [#permalink]

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New post 11 Sep 2008, 05:20
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The vertices of rectangle ABCD are (12,5), (-12,5), (-12,-5) and (12,-5). What is the approximate probability that the coordinate of a random point within the rectangle is such that \(x^2+y^2\)< 25?

12.5%
25%
33%
40%
50%

Kudos [?]: 104 [0], given: 0

SVP
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Joined: 17 Jun 2008
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Re: Zumit PS 012 [#permalink]

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New post 11 Sep 2008, 11:04
It will be the ratio of area of square enclosed within (5,0), (0,5), (-5,0), (0,-5) and the original rectangle and will be approx 25% (~22%).

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Senior Manager
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Re: Zumit PS 012 [#permalink]

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New post 11 Sep 2008, 11:44
scthakur wrote:
It will be the ratio of area of square enclosed within (5,0), (0,5), (-5,0), (0,-5) and the original rectangle and will be approx 25% (~22%).


I think I should be more like "the ratio of area of circle enclosed with in radius 5 and the original rectangle 24 x 10"
Area of rectangle = |12 -(-12)| x |5 -(-5)| = 24 x 10 = 240
Area of any point in circle = Pi*5^2 = 25Pi
25Pi is approximately 25 * 3

Prob[Circle in Rectangle] = 25 * 3/ 24 * 10 = 25 / 80 = around 30 - 34%

Choice C is the correct answer.

Kudos [?]: 43 [0], given: 0

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Kudos [?]: 279 [0], given: 0

Re: Zumit PS 012 [#permalink]

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New post 12 Sep 2008, 05:37
devilmirror wrote:
scthakur wrote:
It will be the ratio of area of square enclosed within (5,0), (0,5), (-5,0), (0,-5) and the original rectangle and will be approx 25% (~22%).


I think I should be more like "the ratio of area of circle enclosed with in radius 5 and the original rectangle 24 x 10"
Area of rectangle = |12 -(-12)| x |5 -(-5)| = 24 x 10 = 240
Area of any point in circle = Pi*5^2 = 25Pi
25Pi is approximately 25 * 3

Prob[Circle in Rectangle] = 25 * 3/ 24 * 10 = 25 / 80 = around 30 - 34%

Choice C is the correct answer.


Thanks devilmirror for correcting.....committed another silly mistake.....hope do not do during the first 15-20 questions in the actual test. :(

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Re: Zumit PS 012   [#permalink] 12 Sep 2008, 05:37
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The vertices of rectangle ABCD are (12,5), (-12,5), (-12,-5)

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