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The weight of an iron bucket increases by 33.33% when filled [#permalink]
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26 Aug 2009, 03:30
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The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers? 1. 7 kg 2. 6 kg 3. 5 kg 4. 8 kg
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Re: Percentage again [#permalink]
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26 Aug 2009, 03:47
W=weight of bucket V=volume of bucket W + 0,5V = 1,33W so 0,5V = 0,33W it wants us (W+V)/2 that is (W + 0,66W)/2= 0,83W But we do not know anything else. So anyone can be. But the sentence in paranthesis gives us a clue. Capacity of bucket and weight of bucket are integer. So W and 0,66W is integer. i.e. W and 2/3W is integer. So we can assume that W is a multiple of 3 (say 3n) . And 0,66 W is a multiple of 2 (say 2n). So they make a multiple of 5 together (3n+2n). So the answer, IMO, 3.



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Re: Percentage again [#permalink]
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08 Sep 2010, 03:29
Bunuel, can you please look at this question? I agree with the solution by maliyeci but I don't think that multiple of 2 + multiple of 3 equals multiple of 5 (eg., 18+4 = 22). Thank you.



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Re: Percentage again [#permalink]
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08 Sep 2010, 06:55
virtualanimosity wrote: Q. The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?
1. 7 kg 2. 6 kg 3. 5 kg 4. 8 kg rets try some numbers. Say IronB = 6 kg EMPTY so filled with 50% water you have a 1/3*6 = 2 kg water weight. so adding the rest of the bucket with water will naturally increase it by another 2kg so you have 2+2+6 = 10 thus 50% of 10 = 5. Hope it helps
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Re: Percentage again [#permalink]
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08 Sep 2010, 07:05
shaselai wrote: virtualanimosity wrote: Q. The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?
1. 7 kg 2. 6 kg 3. 5 kg 4. 8 kg rets try some numbers. Say IronB = 6 kg EMPTY so filled with 50% water you have a 1/3*6 = 2 kg water weight. so adding the rest of the bucket with water will naturally increase it by another 2kg so you have 2+2+6 = 10 thus 50% of 10 = 5. Hope it helps Hey thanks a lot. My algebra is not that strong, your explanation a lot more sense to me! Thanks, Dawgie
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Re: Percentage again [#permalink]
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08 Sep 2010, 07:18
virtualanimosity wrote: Q. The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?
1. 7 kg 2. 6 kg 3. 5 kg 4. 8 kg \(\frac{bucket}{50% \ water}=\frac{3}{1}\) > \(\frac{bucket}{100% \ water}=\frac{3}{1+1}=\frac{3}{2}\) > as the weight of bucket and its capacity in kg are integers then the weight of bucket full with water will be a multiple of 3+2=5 (5, 10, 15, 20, ...) > half of this weight will be 2.5, 5, 7.5, 10, ... Only answer matching this possible values is 5 kg. Answer: 3 (5 kg).
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Re: Percentage again [#permalink]
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09 Sep 2010, 01:55
Guys, thanks for your explanations but I don't get either.
In shaselai's solution I don't understand if we can pick a different number than 6.
In Bunuel's solution I don't get how he got the first expression.
Thank you.



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Re: Percentage again [#permalink]
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09 Sep 2010, 01:59



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Re: Percentage again [#permalink]
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09 Sep 2010, 03:50
Bunuel, thanks a lot. I got it.



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Re: The weight of an iron bucket increases by 33.33% when filled [#permalink]
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03 Sep 2017, 23:02
Let,the weight of the bucket = x; So, weight of the bucket when it contains 50% water = (x+x/3)=4x/3 [since, the weight increases by 33.33%]
So when it contains 100% water the weight will be = (4x/3)+(x/3)=5x/3 [As, the weight of 50% water is x/3 other 50% will also be x/3]
Now , the total weight = 5x/3 So , half will be 5x/6 Now according to the qs weight of bucket and its capacity must be integer so,if we check the options, 5x/6 = 7 (wrong) 5x/6 = 6 (wrong) 5x/6 = 5 (correct,since in that case x will be an integer) 5x/6 = 8 (wrong) so,option 3 is correct
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Re: The weight of an iron bucket increases by 33.33% when filled [#permalink]
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11 Sep 2017, 23:21
Bunuel wrote: virtualanimosity wrote: Q. The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?
1. 7 kg 2. 6 kg 3. 5 kg 4. 8 kg \(\frac{bucket}{50% \ water}=\frac{3}{1}\) > \(\frac{bucket}{100% \ water}=\frac{3}{1+1}=\frac{3}{2}\) > as the weight of bucket and its capacity in kg are integers then the weight of bucket full with water will be a multiple of 3+2=5 (5, 10, 15, 20, ...) > half of this weight will be 2.5, 5, 7.5, 10, ... Only answer matching this possible values is 5 kg. Answer: 3 (5 kg). hi The weight of a bucket increases by 33.33% that is 1/3 when filled with 50% of water, so when filled with 100% of water the wight will increase by 2/3....so far so good ...however, can you please speak few more words about the operation "3+2 = 5"...? Is this something as such that the ratio of water to bucket is 2:3...so, the water and weight in kg have to be divisible by (2+3), for the condition to hold true that weight and water in kg are integers....? please say to me whether this is okay .....? thanks in advance , man ...




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