u1983 wrote:
Hello Seniors :
In the GMAT CLUB math book I found :
For a cylinder of radius r inscribed in a sphere of radius R (R greater than r)
Height of the cylinder is 2(\(\sqrt{{R^2-r^2}}\))
Could not deduct myself.......could any one help
Hi
u1983 ,
Please refer the below diagram:
Attachment:
Cylinder_Sphere.png [ 10.84 KiB | Viewed 490 times ]
In the right angle triangle ABC , by applying Pythagoras theorem we have following:
\(r^2 + (\frac{h}{2})^2 = R^2\)
After simplifying, we get:
\(\Rightarrow h = 2 \sqrt{R^2 - r^2}\)
Hope this helps.
Thanks.