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DLMD
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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 13:02
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There are 2 sets, A and B. All the number in set B are also in Set A. Is the range of set A more than the range of the set B?
(1) there are same number of member in set A and B
(2) there are 2 more member in set A than in set B



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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 13:08
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I'll pick E

I have no idea what the numbers are from either statement, range is defined as "largest number minus smallest number". Since both statetments dont add anything to this, I pick E

less than 20 sec to do this...i hope I am right!
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maaverick
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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 13:47
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I'll pick A

n(A) = n(B) and since all the numbers of set B are also present in set A, it implies that they are identical sets.
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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 14:21
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I say A as well. If A and B has the same number of members and all of set B is in set A then the ranges should be the same because the numbers in A and B are the same which means that the range of A cannot be greater than B.

If A has two more you don't know if the range is the same, more or less unless you know the value of the numbers in A and B.
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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 15:41
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Statement 1 is sufficient to answer the question

Statement 2 is not sufficient since the range of set A can be larger, equal to the range of set B – Not sufficient

The answer is A
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There are 2 sets, A and B. All the number in set B are also 14 Jan 2005, 18:19
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Statement 1 and Statement 2 contradict each other. ETS does not give out contradicting statments in DS.
Assuming we can forgive this. Answer is A like explained by someone earlier.



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