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Re: There are 4 more women than men on Centerville's board of
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19 Sep 2014, 15:27

I didn't set up this equation correctly. How is the algebra reasoning for this question diff than Q 29? When do we know that we need to set up 2 diff equations representing 2 diff variables?

There are 4 more women than men on Centerville's board of
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26 Feb 2018, 07:07

Let M be the no of men. Let Women be expressed in terms of M ie W = M+4 We also know Men + Women = 10 therefore M + M+4 = 10 Solving the equation we get 2m = 6 and m = 3. Since there are 4 more women than men the total no of women = 3+ 4 = 7 . The question asks for the no of women = 7 is the answer The ans also fits into the constrain in the q = total = 10 ( 3 + 7 )

We can also solve this by testing the ans choices Eg : With C = 6 women + 2 men =8 is incorrect as the total no of members needs to be 10 on the board. It also means ans choice a & B are also wrong as it wont suffice the constrain. Lets check ans choice d = 7 women = 3 men = 7+ 3 = 10 = correct . Therfore ans choce = D

gmatclubot

There are 4 more women than men on Centerville's board of &nbs
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26 Feb 2018, 07:07