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Bunuel
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Bunuel
There are 40 students in a classroom, 9/20 of students are boys and 4/5 of students are right-handed. What is the minimum number of right-handed boys possible?

A. 10
B. 12
C. 14
D. 16
E. 18
---B----NB--total
RH--10--24--32
LH---8---0---8
total--18--22--40

IMO A ; 10
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Number of boys --> 18
Number of girls --> 22

No of right handed students --> 24

Minimum of boys that are right handed is 18/40 * 24 which equals 10.8 and since there can't be 0.8 boys, the minimum no is 10
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Total students = 40

Boys = (9/20)*40 = 18

So, Girls = 40 - 18 = 22

Right-handed = (4/5)*40 = 32

In order for the number of right-handed boys to be minimum, the number of right-handed girls needs to be maximum and that is possible if all of the 22 girls in the classroom are right-handed.
In that case, the remaining (32 - 22) = 10 right-handed students will be the minimum number of boys.

Hence, option (A).
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