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FN
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I go the step by step :

Given: Median: 200 - Q: is range >80

St1: Avg= 240 (now why guys assumed 200 for 3 I dont know!!!) this is insufficient as it doesnt help us to find the range as tht could be < or >80 depending on the way u choose numbers

St2: 3 of them are 200 => {a, b, 200, 200, 200} or {200, 200, 200, a, b} is the set. we dont know anything abt a, b -----insuff

St1 +2: now we have a+b = 600 now the minimum value the range can take is when a=b=300

Hence C.

I go with it!!!!


EDIT: Guess wanted to prove the OA!!! :twisted:

I understand that A should be suffic.
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fresinha12
There are 5 books, the median value is $200. Is the range bigger than $80?
(1) the avg mean of the 5 books is $240
(2) 3 of the 5 books have the same price

A. To have 200.00 as a median price at least two other books should have a price less than 200 or equal to it. Since median is 200.00 and the average is 240.00, lets assume the followings:

Book 1 + Book 2 + median Book + x + x = 240 x 5
200 + 200 + 200 + x + x = 1200
600 + 2x = 1200
x = 300

so the range is > 80. so A.

B clearly is insufficient.



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