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Re: There are 8 job applicants sitting in a waiting room4 women and 4 men [#permalink]
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SajjadAhmad wrote:
There are 8 job applicants sitting in a waiting room—4 women and 4 men. If 2 of the applicants are selected at random, what is the probability that both will be women?

A. \(\frac{1}{4}\)

B. \(\frac{3}{7}\)

C. \(\frac{5}{2}\)

D. \(\frac{3}{14}\)

E. \(\frac{1}{10}\)



solve using probability method

\(\frac{4}{8}*\frac{3}{7} = \frac{12'}{56} = \frac{3}{14}\)

solve using combinatorics

Total number of ways \(P^8_2\) = \(24\)

Number of ways to choose two women out of 4 \(P^4_2\) = \(6\)

Number of ways to choose both women from 8 persons \(\frac{6}{24}\)
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Re: There are 8 job applicants sitting in a waiting room4 women and 4 men [#permalink]
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Sajjad1994 wrote:
There are 8 job applicants sitting in a waiting room—4 women and 4 men. If 2 of the applicants are selected at random, what is the probability that both will be women?

A. \(\frac{1}{4}\)

B. \(\frac{3}{7}\)

C. \(\frac{5}{2}\)

D. \(\frac{3}{14}\)

E. \(\frac{1}{10}\)


The probability that two women are selected is as follows:

4/8 x 3/7 = 1/2 x 3/7 = 3/14.

Answer: D
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Re: There are 8 job applicants sitting in a waiting room4 women and 4 men [#permalink]
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