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27 Mar 2019, 11:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
60% (01:17) correct
40%
(01:37)
wrong
based on 142
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There are eight people in a certain club, including Bob and Ted. If the club is to select a 4 people committee that include Bob but not include Ted, how many different such committees are possible?
(A) 20
(B) 28
(C) 30
(D) 35
(E) 56
(A) 20
(B) 28
(C) 30
(D) 35
(E) 56
27 Mar 2019, 12:47
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Just remove Bob and Ted from the calculation.
6C3 = 20
6C3 = 20
29 Mar 2019, 10:32
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Using slot method:
We have to include Bob but exclude Ted, so we have to choose 4 people out of 8-1=7 (because Ted is no longer a candidate): Bobx6x5x4=120. Now, since order doesn't matter among the remaining 3 members, we have to exclude their arrangement possibilities as well by dividing 3!: 120/3!=120/6=20
Answer is A.
We have to include Bob but exclude Ted, so we have to choose 4 people out of 8-1=7 (because Ted is no longer a candidate): Bobx6x5x4=120. Now, since order doesn't matter among the remaining 3 members, we have to exclude their arrangement possibilities as well by dividing 3!: 120/3!=120/6=20
Answer is A.
