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# There are five homes. If the median price of a home is \$200,000

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Manager
Joined: 03 Mar 2018
Posts: 215
There are five homes. If the median price of a home is \$200,000  [#permalink]

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28 Mar 2018, 06:18
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85% (hard)

Question Stats:

46% (02:05) correct 54% (02:37) wrong based on 131 sessions

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There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

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Re: There are five homes. If the median price of a home is \$200,000  [#permalink]

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28 Mar 2018, 10:01
2
itisSheldon wrote:
There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

Statement 1:
Average price of 5 homes = \$240,000. This means total price of 5 homes = 5*240000 = \$1,200,000.
To keep our range minimum, we should try to keep smallest and largest values (out of these 5) as close as possible.
Our smallest value can go up to 200,000 (since thats the median), and in that case, first 3 values will be 200,000 only.

So let the price of first 3 homes be \$200,000 each. This makes it \$600,000. Remaining price of 2 costlier homes = 1,200,000 - 600,000 = \$600,000
In this case, costliest room will get the smallest value if we assume price of 4th and 5th homes to be equal, i.e., \$300,000 each.

So here we have accomplished the purpose of keeping the smallest and largest value as close as possible. And the range in this case = price of highest - price of lowest = 300,000 - 200,000 = \$100,000. So when here only the range is more than \$80,000 then in any other case it will definitely be more than \$80,000. Sufficient.

Statement 2:
Which three homes have same price we don't know. And also this doesn't help in determining the range. So not sufficient.

Manager
Joined: 01 Feb 2018
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Location: India
Concentration: Entrepreneurship, Marketing
GPA: 4
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There are five homes. If the median price of a home is \$200,000  [#permalink]

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07 Apr 2018, 05:27
amanvermagmat wrote:
itisSheldon wrote:
There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

Statement 1:
Average price of 5 homes = \$240,000. This means total price of 5 homes = 5*240000 = \$1,200,000.
To keep our range minimum, we should try to keep smallest and largest values (out of these 5) as close as possible.
Our smallest value can go up to 200,000 (since thats the median), and in that case, first 3 values will be 200,000 only.

So let the price of first 3 homes be \$200,000 each. This makes it \$600,000. Remaining price of 2 costlier homes = 1,200,000 - 600,000 = \$600,000
In this case, costliest room will get the smallest value if we assume price of 4th and 5th homes to be equal, i.e., \$300,000 each.

So here we have accomplished the purpose of keeping the smallest and largest value as close as possible. And the range in this case = price of highest - price of lowest = 300,000 - 200,000 = \$100,000. So when here only the range is more than \$80,000 then in any other case it will definitely be more than \$80,000. Sufficient.

Statement 2:
Which three homes have same price we don't know. And also this doesn't help in determining the range. So not sufficient.

I think even B is sufficient.... working for option B.

even though we dont know which 2 houses have same price, we have to make either of the choices.. as there are only two choices available if we keep house in ascending order of their value.

choice I : 1, 2 & 3 have same price
Choice II : 2, 3 & 4 have same price

Choice I : 1 2 & 3 have same price, since the median is known to us 200000. price of 1, 2 & 3 totals to 600,000 and rest 3 & 4 have a value of 600,000.

now whatever value we give to 4 & 5 range is going to be more than 80,000.

Choice II : 2 3 & 4 have same price, again as we know median is 200000. price of 2 3 & 4 totals to 600,000 and rest 1 & 5 have a value of 600,000.

now whatever value we give to 1 & 5 range is going to be more than 80,000.

Hence under both choices we get same answer that is range of all prices IS greater than \$80,000. so even B is sufficient statement.

pls help me, if m on the wrong track !!
Manager
Joined: 03 Mar 2018
Posts: 215
There are five homes. If the median price of a home is \$200,000  [#permalink]

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07 Apr 2018, 06:33
1
GMAT215 wrote:
amanvermagmat wrote:
itisSheldon wrote:
There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

Statement 1:
Average price of 5 homes = \$240,000. This means total price of 5 homes = 5*240000 = \$1,200,000.
To keep our range minimum, we should try to keep smallest and largest values (out of these 5) as close as possible.
Our smallest value can go up to 200,000 (since thats the median), and in that case, first 3 values will be 200,000 only.

So let the price of first 3 homes be \$200,000 each. This makes it \$600,000. Remaining price of 2 costlier homes = 1,200,000 - 600,000 = \$600,000
In this case, costliest room will get the smallest value if we assume price of 4th and 5th homes to be equal, i.e., \$300,000 each.

So here we have accomplished the purpose of keeping the smallest and largest value as close as possible. And the range in this case = price of highest - price of lowest = 300,000 - 200,000 = \$100,000. So when here only the range is more than \$80,000 then in any other case it will definitely be more than \$80,000. Sufficient.

Statement 2:
Which three homes have same price we don't know. And also this doesn't help in determining the range. So not sufficient.

I think even B is sufficient.... working for option B.

even though we dont know which 2 houses have same price, we have to make either of the choices.. as there are only two choices available if we keep house in ascending order of their value.

choice I : 1, 2 & 3 have same price
Choice II : 2, 3 & 4 have same price

Choice I : 1 2 & 3 have same price, since the median is known to us 200000. price of 1, 2 & 3 totals to 600,000 and rest 3 & 4 have a value of 600,000.

now whatever value we give to 4 & 5 range is going to be more than 80,000.

Choice II : 2 3 & 4 have same price, again as we know median is 200000. price of 2 3 & 4 totals to 600,000 and rest 1 & 5 have a value of 600,000.

now whatever value we give to 1 & 5 range is going to be more than 80,000.

Hence under both choices we get same answer that is range of all prices IS greater than \$80,000. so even B is sufficient statement.

pls help me, if m on the wrong track !!

Hey GMAT215
You are falling into the common trap of GMAT DS questions. Using the information of statement 1 in statement 2.
If you exclusively consider Statement 2, You only know that three out of five homes have the same price, but you don't know the average price of five homes.(For instance the average price of five homes can be \$200,000. In that case range of the homes will be zero)
Hope that helps.
For more questions to understand this trap, check this out
https://gmatclub.com/forum/joanna-bough ... 01743.html
https://gmatclub.com/forum/the-centers- ... 12616.html
https://gmatclub.com/forum/if-n-and-k-a ... 83132.html
https://gmatclub.com/forum/15-members-o ... l?fl=email
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Joined: 29 Mar 2015
Posts: 20
GMAT 1: 590 Q44 V23
Re: There are five homes. If the median price of a home is \$200,000  [#permalink]

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09 Apr 2018, 07:33
amanvermagmat wrote:
itisSheldon wrote:
There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

Statement 1:
Average price of 5 homes = \$240,000. This means total price of 5 homes = 5*240000 = \$1,200,000.
To keep our range minimum, we should try to keep smallest and largest values (out of these 5) as close as possible.
Our smallest value can go up to 200,000 (since thats the median), and in that case, first 3 values will be 200,000 only.

[/b]

Hi, how do you know to find the minimum of the range in the first place? Isn't that also true if the maximum of range is smaller than \$80k => range is always smaller than \$80K => SUFFICIENT??
Tks
DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1431
Location: India
Re: There are five homes. If the median price of a home is \$200,000  [#permalink]

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09 Apr 2018, 10:16
akara2500 wrote:
amanvermagmat wrote:
itisSheldon wrote:
There are five homes. If the median price of a home is \$200,000, is the range of all prices greater than \$80,000?

1) The average price of the five homes is \$240,000.
2) Three of five homes have the same price.

Statement 1:
Average price of 5 homes = \$240,000. This means total price of 5 homes = 5*240000 = \$1,200,000.
To keep our range minimum, we should try to keep smallest and largest values (out of these 5) as close as possible.
Our smallest value can go up to 200,000 (since thats the median), and in that case, first 3 values will be 200,000 only.

[/b]

Hi, how do you know to find the minimum of the range in the first place? Isn't that also true if the maximum of range is smaller than \$80k => range is always smaller than \$80K => SUFFICIENT??
Tks

Hello

Yes, if MAX of range is smaller than \$80k; => range is always smaller than \$80k.
Similarly, if MIN of range is greater than \$80k; => range is always greater than \$80k. And thats what I have shown here.
Re: There are five homes. If the median price of a home is \$200,000   [#permalink] 09 Apr 2018, 10:16
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