a*b*c = 4199 , b*c*d= 7429 ---> (b*c) * ( d-a) = 3230 = 323*10
Since b*c can't be a multiple of 10 ---> d-a must be a multiple of 10
since 323 has no factors of 2,3,4,5 ,6, 7 (this we can judge by using divisibility tricks) --->
The best d-a is 10 (coz if d-a = 8 or larger ----> there are A LOT other primes in between ----> violate the "consecutive" characteristics of this sequence)
we have 20*20*20= 8000>> 4199 ----> the least number must be < 20
1) a=2 ---> d=12 , not a prime --> out
2) a=3 ---> d= 13, there're 3 primes in between ---> out
3) a=5 --> d=15 , not a prime ---> out
4) a=7 -->d=17 ---> 7,11,13,17 ...but 7*11*13 has unit digit of 1 instead of 9 ---> out
5) a=11 -->d=21 , not a prime --> out
6) a= 13 ---> d=23 ---> 13,17,19,23 : WOW!
7) a= 17 ---> d=27, not a prime --> out
8) a= 19 ---> d=29 ---> there's only 1 prime in between ---> out
So the best sequence is 13,17,19,23.
It looks redundant but in fact, the reasoning process is very short and quick.