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08 Feb 2024, 02:30
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (02:04) correct
36%
(02:09)
wrong
based on 129
sessions
History
Date
Time
Result
Not Attempted Yet
There are three times as many hot dogs as pizzas and five times as many brownies as hot dogs in "Junk Food 'R' Us" restaurant. The restaurant sells only whole products (you cannot buy half a pizza, for example). How many brownies are there in the restaurant?
(1) There are at least 10 pizzas in the restaurant
(2) There are 32 hot dogs at most in the restaurant
(1) There are at least 10 pizzas in the restaurant
(2) There are 32 hot dogs at most in the restaurant
08 Feb 2024, 12:53
Kudos
Bookmarks
I think C should be Correct
Let's say there's p pizzas => there's 3p hot dogs => there's 15p brownies
So, if we get to know any one of these values, we can calculate the rest 2 values.
Statement 1:
There are at least 10 pizzas in the restaurant
So, \(p\geq{10}\)
that simply means number of brownies = \(15p\geq{150}\)
Nothing conclusive. Because the number can 150 or 165 or 180 and so on.
Insufficient.
Statement 2:
There are 32 hot dogs at most in the restaurant
So, \(3p\leq{32}\) => \(p\leq{10.667}\)
but p can only be an integer so \(p\leq{10}\)
So, number of brownies = \(15p\leq{150}\) => 15p can be 150 or 135 or 120 and so on.
Again, nothing conclusive.
Hence, Insufficient.
If we club them together:
we have \(p\geq{10}\) and \(3p\leq{32}\) => \(p\leq{10}\)
So, \(p\geq{10}\) and \(p\leq{10}\) gives us p=10
i.e, number of brownies = 15p =150
Hence, both statements together are sufficient.
Hence, option C
Let's say there's p pizzas => there's 3p hot dogs => there's 15p brownies
So, if we get to know any one of these values, we can calculate the rest 2 values.
Statement 1:
There are at least 10 pizzas in the restaurant
So, \(p\geq{10}\)
that simply means number of brownies = \(15p\geq{150}\)
Nothing conclusive. Because the number can 150 or 165 or 180 and so on.
Insufficient.
Statement 2:
There are 32 hot dogs at most in the restaurant
So, \(3p\leq{32}\) => \(p\leq{10.667}\)
but p can only be an integer so \(p\leq{10}\)
So, number of brownies = \(15p\leq{150}\) => 15p can be 150 or 135 or 120 and so on.
Again, nothing conclusive.
Hence, Insufficient.
If we club them together:
we have \(p\geq{10}\) and \(3p\leq{32}\) => \(p\leq{10}\)
So, \(p\geq{10}\) and \(p\leq{10}\) gives us p=10
i.e, number of brownies = 15p =150
Hence, both statements together are sufficient.
Hence, option C
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